如何将时间戳插入到Hive表中? [英] How to insert timestamp into a Hive table?
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问题描述
我有以下内容:
hive> CREATE TABLE foo(bar timestamp)STORED AS ORC;
确定
所需时间:0.041秒
配置单元> INSERT INTO TABLE foo VALUES('2014-01-17 00:17:13');
NoViableAltException(26 @ [])
at org.apache.hadoop.hive.ql.parse.HiveParser_SelectClauseParser.selectClause(HiveParser_SelectClauseParser.java:742)
at org.apache.hadoop.hive .org.parse.HiveParser.selectClause(HiveParser.java:40184)
at org.apache.hadoop.hive.ql.parse.HiveParser.singleSelectStatement(HiveParser.java:38048)
at org.apache .hadoop.hive.ql.parse.HiveParser.selectStatement(HiveParser.java:37754)
at org.apache.hadoop.hive.ql.parse.HiveParser.regularBody(HiveParser.java:37654)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpressionBody(HiveParser.java:36898)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpression(HiveParser.java:36774)
at org.apache.hadoop.hive.ql.parse.HiveParser.execStatement(HiveParser.java:1338)
at org.apache.hadoop.hive.ql.parse.HiveParser.statement(HiveParser。 java:1036)
在org.apache.hadoop.hive.ql .parse.ParseDriver.parse(ParseDriver.java:199)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:166)
at org.apache.hadoop .hive.ql.Driver.compile(Driver.java:408)
在org.apache.hadoop.hive.ql.Driver.compile(Driver.java:322)
在org.apache.hadoop .hive.ql.Driver.compileInternal(Driver.java:976)
位于org.apache.hadoop.hive.ql.Driver.runInternal(Driver.java:1041)
位于org.apache.hadoop .hive.ql.Driver.run(Driver.java:912)
在org.apache.hadoop.hive.ql.Driver.run(Driver.java:902)
在org.apache.hadoop .hive.cli.CliDriver.processLocalCmd(CliDriver.java:268)
at org.apache.hadoop.hive.cli.CliDriver.processCmd(CliDriver.java:220)
at org.apache.hadoop .hive.cli.CliDriver.processLine(CliDriver.java:423)
at org.apache.hadoop.hive.cli.CliDriver.executeDriver(CliDriver.java:793)
at org.apache.hadoop .hive.cli.CliDriver.run(CliDriver.java :686)
at org.apache.hadoop.hive.cli.CliDriver.main(CliDriver.java:625)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun (NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java :606)
在org.apache.hadoop.util.RunJar.main(RunJar.java:212)
FAILED:ParseException线1:22无法识别'values'附近的输入''('''2014 -01-17 00:17:13''在select子句中
插入的正确方法是什么时间戳记到Hive表中?
Hive版本是:hive-0.13.0
解决方案 div>
根据 Hive La
因此,您只剩下两个选项:
- 从现有表格插入时间戳值或调用函数来获取它(例如
from_unixtime(unix_timestamp())
,例如,请参阅此答案) - 从文件加载数据。
I have the following:
hive> CREATE TABLE foo (bar timestamp) STORED AS ORC;
OK
Time taken: 0.041 seconds
hive> INSERT INTO TABLE foo VALUES ('2014-01-17 00:17:13');
NoViableAltException(26@[])
at org.apache.hadoop.hive.ql.parse.HiveParser_SelectClauseParser.selectClause(HiveParser_SelectClauseParser.java:742)
at org.apache.hadoop.hive.ql.parse.HiveParser.selectClause(HiveParser.java:40184)
at org.apache.hadoop.hive.ql.parse.HiveParser.singleSelectStatement(HiveParser.java:38048)
at org.apache.hadoop.hive.ql.parse.HiveParser.selectStatement(HiveParser.java:37754)
at org.apache.hadoop.hive.ql.parse.HiveParser.regularBody(HiveParser.java:37654)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpressionBody(HiveParser.java:36898)
at org.apache.hadoop.hive.ql.parse.HiveParser.queryStatementExpression(HiveParser.java:36774)
at org.apache.hadoop.hive.ql.parse.HiveParser.execStatement(HiveParser.java:1338)
at org.apache.hadoop.hive.ql.parse.HiveParser.statement(HiveParser.java:1036)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:199)
at org.apache.hadoop.hive.ql.parse.ParseDriver.parse(ParseDriver.java:166)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:408)
at org.apache.hadoop.hive.ql.Driver.compile(Driver.java:322)
at org.apache.hadoop.hive.ql.Driver.compileInternal(Driver.java:976)
at org.apache.hadoop.hive.ql.Driver.runInternal(Driver.java:1041)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:912)
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:902)
at org.apache.hadoop.hive.cli.CliDriver.processLocalCmd(CliDriver.java:268)
at org.apache.hadoop.hive.cli.CliDriver.processCmd(CliDriver.java:220)
at org.apache.hadoop.hive.cli.CliDriver.processLine(CliDriver.java:423)
at org.apache.hadoop.hive.cli.CliDriver.executeDriver(CliDriver.java:793)
at org.apache.hadoop.hive.cli.CliDriver.run(CliDriver.java:686)
at org.apache.hadoop.hive.cli.CliDriver.main(CliDriver.java:625)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:606)
at org.apache.hadoop.util.RunJar.main(RunJar.java:212)
FAILED: ParseException line 1:22 cannot recognize input near 'values' '(' ''2014-01-17 00:17:13'' in select clause
What is the correct way of inserting timestamps into a Hive table?
Hive version is: hive-0.13.0
解决方案
According to Hive Language Manual "INSERT...VALUES is available starting in Hive 0.14".
So, you have only two options left:
- Insert timestamp value from existing table or call a function to get it (e.g.
from_unixtime(unix_timestamp())
, see this answer for example) - Load data from a file.
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