URI以两个斜杠开头......他们的行为如何？ [英] URI starting with two slashes ... how do they behave?

问题描述

 < script type =
 text / javascriptsrc =// ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js\"> ;</script>根据RFC 2396（URI语法）和RFC 2616（HTTP 1.1），这些以2开头的URI斜杠是有效的，但不幸的是，RFC并没有真正解释它们。
 
 
任何人都可以指定一个资源来解释浏览器将如何处理这些URI？ 
解决方案
您正在寻找的资源是 RFC 3986 。 
 
 
请参阅第4.2节和第5.4节。引用后者：
 $ b 
 
 
 参考解析示例 
 
 
 
在具有明确定义的基本URI的表示中：
 
 
 
 
  http：// a / b / c / d; p？q 
  
 
 
 
 
 
相对引用是转换为目标URI如下： 
 
 
 g：h=g：h
g =http：// a / b / c / g
./g=http：// a / b / c / g
g /=http：/ / a / b / c / g /
/ g=http：// a / g
// g=http：// g
 ？y=http：// a / b / c / d; p？y
g？y=http：// a / b / c / g？y
 #s=http：// a / b / c / d; p？q＃s
g＃s=http：// a / b / c / g＃s
g？y＃s=http：// a / b / c / g？y＃s
; x=http：// a / b / c /; x 
g; x=http：// a / b / c / g; x
g; x？y＃s=http：// a / b / c / g; x？y＃s
=http：// a / b / c / d; p？q
。 =http：// a / b / c /
./=http：// a / b / c /
..=http：// a / b /
../=http：// a / b /
../g=http：// a / b / g
 ../ ..=http：// a /
../../=http：// a /
../../g= http：// a / g
  
 
 
这意味着当基础URI是 http：// a / b / c / d; p？q 并且您使用 // g ，相对引用被转换为 http：// g 。
 
Lately I saw working code-blocks like this:
<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
And according to RFC 2396 (URI Syntax) and RFC 2616 (HTTP 1.1) these URI starting with two slashes are valid, but unfortunately the RFCs don't really explain them.

Can anyone point me to a resource which explains how browsers will/should/do process these URIs?
解决方案
The resource you're looking for is the RFC 3986.

See Section 4.2 and Section 5.4. Quoting from the latter:

  
Reference Resolution Examples
  
  
Within a representation with a well defined base URI of:


    http://a/b/c/d;p?q



  
a relative reference is transformed to its target URI as follows:
  "g:h"           =  "g:h"
  "g"             =  "http://a/b/c/g"
  "./g"           =  "http://a/b/c/g"
  "g/"            =  "http://a/b/c/g/"
  "/g"            =  "http://a/g"
  "//g"           =  "http://g"
  "?y"            =  "http://a/b/c/d;p?y"
  "g?y"           =  "http://a/b/c/g?y"
  "#s"            =  "http://a/b/c/d;p?q#s"
  "g#s"           =  "http://a/b/c/g#s"
  "g?y#s"         =  "http://a/b/c/g?y#s"
  ";x"            =  "http://a/b/c/;x"
  "g;x"           =  "http://a/b/c/g;x"
  "g;x?y#s"       =  "http://a/b/c/g;x?y#s"
  ""              =  "http://a/b/c/d;p?q"
  "."             =  "http://a/b/c/"
  "./"            =  "http://a/b/c/"
  ".."            =  "http://a/b/"
  "../"           =  "http://a/b/"
  "../g"          =  "http://a/b/g"
  "../.."         =  "http://a/"
  "../../"        =  "http://a/"
  "../../g"       =  "http://a/g"

This means that when the base URI is http://a/b/c/d;p?q and you use //g, the relative reference is transformed to http://g.

                        
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