用PHP获取img src [英] Get img src with PHP
问题描述
< img border =0我想在这个例子中将SRC属性变成一个变量: src =/ images / image.jpgalt =Imagewidth =100height =100/>
例如 - 我想获得一个变量 $ foo = /images/image.jpg
。
重要! src属性将是动态的,所以它不能被硬编码。
有没有什么快捷的方法可以做到这一点?
谢谢!
编辑:The图像将成为一个巨大的字符串的一部分,基本上是新闻报道的内容。所以图像只是其中的一部分。
编辑2:这个字符串中会有更多的图像,我只想得到第一个图像的src。这可能吗?
使用HTML解析器,如 DOMDocument
,然后使用 DOMXpath
评估您要查找的值:
$ html ='< img id =12border =0src =/ images / image.jpg
alt =Imagewidth =100height =100/>';
$ doc = new DOMDocument();
$ doc-> loadHTML($ html);
$ xpath = new DOMXPath($ doc);
$ src = $ xpath-> evaluate(string(// img / @ src)); #/images/image.jpg
或者对于那些真正需要节省空间的人:
$ xpath = new DOMXPath(@DOMDocument :: loadHTML($ html));
$ src = $ xpath-> evaluate(string(// img / @ src));
对于单线队员来说:
$ src =(string)reset(simplexml_import_dom(DOMDocument :: loadHTML($ html)) - > xpath(// img / @ src));
I would like to get the SRC attribute into a variable in this example:
<img border="0" src="/images/image.jpg" alt="Image" width="100" height="100" />
So for example - I would like to get a variable $foo = "/images/image.jpg"
.
Important! The src attribute will be dynamic, so it mustn't be hardcoded.
Is there any quick and easy way to do this?
Thanks!
EDIT: The image will be a part of a huge string that is basically the content of a news story. So the image is just a part of that.
EDIT2: There will be more images in this string, and I would only want to get the src of the first one. Is this possible?
Use a HTML parser like DOMDocument
and then evaluate the value you're looking for with DOMXpath
:
$html = '<img id="12" border="0" src="/images/image.jpg"
alt="Image" width="100" height="100" />';
$doc = new DOMDocument();
$doc->loadHTML($html);
$xpath = new DOMXPath($doc);
$src = $xpath->evaluate("string(//img/@src)"); # "/images/image.jpg"
Or for those who really need to save space:
$xpath = new DOMXPath(@DOMDocument::loadHTML($html));
$src = $xpath->evaluate("string(//img/@src)");
And for the one-liners out there:
$src = (string) reset(simplexml_import_dom(DOMDocument::loadHTML($html))->xpath("//img/@src"));
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