在提交之前过滤表单参数 [英] Filter Form Parameters Before Submitting

问题描述

 < form method =GET 
有没有办法在提交之前检查参数是否为空？ > 
< input name =param1value =test/> 
< input name =param2value =/> 
< input type =submitname =id =search-submitclass =buttonvalue =Submit> 
< / form> 
  

如果我有一个这样的表单。 param2是空的，所以当我按提交时，它看起来像这样

  link.com?param1=test&param2= 
  

所以当param为空时，可以达到这样的效果。它不应该包括在内。
like

  link.com?param1=test 
   
 
 
纯净的javascript方法
   p> 
 
 
  form.onsubmit = function（）{
 var arr = this.elements，i = 0，l = arr.length ; （$; $ i $）
 if（arr [i] .value ===''）{
 arr [i] .disabled = true; 
 
 
 
 
 
 $ p $要回答OP的进一步问题
 函数checkForm（）{
 var arr = this.elements，i = 0，l = arr.length; （$; $ i $）
 if（arr [i] .value ===''）{
 arr [i] .disabled = true; 
 
 
 
 var arr = document.getElementsByTagName（'form'），i = 0，l = arr.length; 
 for（; i  arr [i] .onsubmit = checkForm; 
} 
  
 
Is there a way to check the parameter if its empty or not before submitting?
<form method="GET">
    <input name="param1" value="test"/>
    <input name="param2" value=""/>
    <input type="submit" name="" id="search-submit" class="button" value="Submit">
</form>
If i have a form something like this. the param2 is empty so when I press submit, it look like this
link.com?param1=test&param2=
so is it possible to attain something like this that when a param is empty. it should not be included.
like
link.com?param1=test
since the param2 is empty
解决方案
Pure javascript method
form.onsubmit=function(){
  var arr=this.elements,i=0,l=arr.length;
  for(;i<l;i++){
    if(arr[i].value===''){
      arr[i].disabled=true;
    }
  }
}
To answer OP's further question
function checkForm(){
  var arr=this.elements,i=0,l=arr.length;
  for(;i<l;i++){
    if(arr[i].value===''){
      arr[i].disabled=true;
    }
  }
}
var arr=document.getElementsByTagName('form'),i=0,l=arr.length;
for(;i<l;i++){
  arr[i].onsubmit=checkForm;
}


                        
这篇关于在提交之前过滤表单参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！