只显示使用PHP显示的标题的第一个字 [英] Only first word of title retrieved with PHP showing

问题描述

因此，我试图在我的另一个网站上显示一个列表，它一切正常，但只存储'标题'属性的第一个单词。我知道整个标题是从其他网站检索的，所以我如何获得它来存储所有的标题。

如果有帮助，以下是代码。

 <？php 
包含simple_html_dom.php; 
 $ page = file_get_html（http://www.blade-edge.com/images/KSA/Flights/craft.asp?r=true&db=dunai）; 
 echo< table id = list>; 
 foreach（$ page-> find（'html / body / div / div [2] / ol / a'）as $ key => $ element）{
 if（$ element-> ; title！=此SOI内没有任何工艺）{
 $ ships [$ key] = $ element-> plaintext; 
 $ shipTitles [$ key] = $ element-> title; 
 $ shipLinks [$ key] = $ element-> href; 
回显< tr>; 
 echo< td title =。$ shipTitles [$ key]。>; 
 echo $ ships [$ key]; 
回声< / td>; 
回声< / tr>; 
} 
} 
 echo< / table>; 
？> 
  

解决方案

将标题放在引号内

  echo< td title =。$ shipTitles [$ key]。>; //错误
  

正确的是

  echo< td title ='。$ shipTitles [$ key]。'>; 
  

如果没有引号，您将只能看到第一个空格的单词

So I am trying to display a list from another website in mine, it all works fine but only the first word of the 'title' attribute is stored. I know that the whole title is retrieved from the other website so how do I get it to store all of it.

Here is the code if it helps.

<?php
include "simple_html_dom.php";
$page = file_get_html("http://www.blade-edge.com/images/KSA/Flights/craft.asp?r=true&db=dunai");
echo "<table id=list>"; 
foreach($page->find('html/body/div/div[2]/ol/a') as $key=>$element) {
    if ($element->title != "No craft within this SOI"){
        $ships[$key] = $element->plaintext;
        $shipTitles[$key] = $element->title;
        $shipLinks[$key] = $element->href;
        echo "<tr>"; 
        echo "<td title =".$shipTitles[$key]." >";
        echo $ships[$key];
        echo "</td>";
        echo "</tr>";
    }
}
echo "</table>";
?>

解决方案

Put title inside quotation marks

echo "<td title =".$shipTitles[$key]." >";   // Wrong

Right is

echo "<td title ='".$shipTitles[$key]."' >";

Without quotes, you will only see the word till the first space

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