提交表单到行动的PHP文件 [英] Submit form to action php file

问题描述

我有一个表单，当用户点击提交时，我需要运行一个php文件。

 < form action =php_scripts / test.phpmethod =POST > 
< input name =featuretype =textplaceholder =Feature/> 
< input name =feature2type =textplaceholder =Feature2/> 
< input type =submitvalue =submit/> 
< / form> 
  

test.php

 <？php 
 
 if（isset（$ _ GET ['submit']））
 {
 $ feature = $ _POST ['feature'] ; 
 // do stuff（将数据发送到数据库）
} 
？> 
  

我遇到的问题是，当我在表单上按提交时，

  if（isset（$ _ GET ['submit']））
  

总是返回false。

任何人都可以解释这是为什么吗？我完全误解了如何实现向PHP脚本发送数据的形式？

如果我犯了任何语法错误，并且非常感谢您提供任何帮助，请致歉。

解决方案

您的代码有一些错误。

将GET与POST方法混合使用。另外，为您的输入添加值并且您的提交按钮未命名，您试图将其用作条件语句。

$ b $ p

 < form action =php_scripts / test.phpmethod =POST> 
< input name =featurevalue =featuretype =textplaceholder =Feature/> 
< input name =feature2value =feature2type =textplaceholder =Feature2/> 
< input type =submitname =submitvalue =submit/> 
< / form> 
  

PHP

  
 if（isset（$ _ POST ['submit']））
 {
 $ feature = $ _POST ['feature']; 
 $ feature2 = $ _POST ['feature2']; 
 // do stuff（将数据发送到数据库）
} 
？> 
  

旁注：您可以/也应该检查空值。

  if（isset（$ _ POST ['submit']）
&&！empty（$ _ POST ['feature']）
 &&！empty（$ _ POST ['feature2']））{...} 
  

---

脚注：

看到您打算发送给DB：

我希望你计划使用 mysqli with prepared statements 或 包含准备好的语句的PDO 。

I have a form where when the user clicks submit, I need a php file to be ran. below is the form and the php file.

<form action="php_scripts/test.php" method="POST">
        <input name="feature"     type = "text"     placeholder="Feature"   /> 
        <input name="feature2"   type = "text"  placeholder="Feature2"  /> 
        <input type="submit" value = "submit"/>
</form>

test.php

<?php

    if( isset($_GET['submit']) )
    {
        $feature = $_POST['feature'];
        // do stuff (will send data to database)
    }
?>

The problem I am having is that when I press Submit on the form,

if( isset($_GET['submit']) )

Always returns false.

Can anyone explain why that is? Have I totally misunderstood how to implement form sending data to php scripts?

Apologies if I have made any syntax errors and many thanks for any help you can give.

解决方案

There are a few things wrong with your code.

You're mixing GET with POST methods. Plus, add values to your inputs and your submit button isn't named, which you're trying to use as a conditional statement for.

HTML

<form action="php_scripts/test.php" method="POST">
        <input name="feature"  value="feature" type = "text" placeholder="Feature" /> 
        <input name="feature2" value="feature2" type = "text"  placeholder="Feature2"  /> 
        <input type="submit" name="submit" value = "submit"/>
</form>

PHP

<?php

    if( isset($_POST['submit']) )
    {
        $feature = $_POST['feature'];
        $feature2 = $_POST['feature2'];
        // do stuff (will send data to database)
    }
?>

Sidenote: You could/should also check against empty values.

if(isset($_POST['submit']) 
    && !empty($_POST['feature']) 
    && !empty($_POST['feature2']) ) {...}

---

Footnotes:

Seeing that you're intending on sending to DB:

I hope you plan on using mysqli with prepared statements, or PDO with prepared statements.

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