用于选择文章的一部分的XPath [英] XPath for selecting a section of an article

问题描述

假设某篇文章的内容如下（html源代码）：

 < h2>简介< / h2> ; 
 ... 
< h2>参考文献< / h2> 
 ...一堆文本... 
< h2>其他阅读< / h2> //可选
 ..... 
  

我想知道是否可以用XPath表达式提取上面例子中的References部分？

我试过类似于 // h2 [contains（。，'References'] / following :: * ，但是我不知道如何指定我想要的部分的结束，它返回文档的其余部分。

解决方案

如果你想要元素直到下一个h2使用这样的xpath

  // * [ -sibling :: h2 [包含（。，'References'）]]和之前的sibling :: h2 [contains（。，'References'）]] 
  

Wath是否表示：它找到所有元素



- - 包含'参考文献'的第一个h2的前面h2包含'参考文献'



- 返回包含'参考文献'的h2

第一条规则从xml的开始到下一个h2标签都采用了所有的元素。第二条规则 - 必要的h2标签到e nd of xml。它们的相交给出了需要的元素。

或者xpath可能建立在您的建议之上：

<$ p $ （包含（。，'References'）]和not（name（））。 ）='h2'）]


必要之后全部h2标签 // h2 [。='参考文献'] / following-sibling :: * 这不是h2，并且有h2标签作为第一个h2之前

Suppose a section of an article is as follows (the html source):

<h2>Introduction</h2>
  ....
<h2>References</h2>
  ...a bunch of text...
<h2>Further Readings</h2>  //optional
  .....

I like to know is it possible with an XPath expression extract the "References" part in the example above?

I tried something like //h2[contains(.,'References']/following::*, however I don't know how to specify the end of my desired section, it returns the rest of document.

解决方案

if you want elements until next h2 use such xpath

//*[following-sibling::h2[preceding-sibling::h2[1][contains(.,'References')]]  and preceding-sibling::h2[contains(.,'References')]]

Wath does it mean: it finds all element which has

-- ahead h2 which has the 1st preceding h2 containing 'References'

-- back h2 containing 'References'

The 1st rule takes all elements from begining of xml until next h2 tag. The 2nd -all after necessary h2 tag to end of xml. Intersection of them gives needed elements.

Or xpath maybe build on your suggestion:

//h2[.='References']/following-sibling::*[preceding-sibling::h2[1][contains(.,'References')] and not(name()='h2')]

take all after necessary h2 tag //h2[.='References']/following-sibling::* which is not h2 and has our h2 tag as the 1st h2 before

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