用于Xml到表转换的XSL [英] XSL for Xml to table transformation

问题描述

继续我昨天的xslt问题，链接如下。

第一个倒数第二个变体

我必须输出每个部分的第一个和最后一个页码到一个表中。

<我很困惑从哪里开始。非常感谢XSLT 1.0解决方案和XSLT 2.0解决方案。我非常感谢任何帮助。

问候JJ。

输入：

 < root> 
< page number =1section =Arsenal>阿森纳< / page> 
< page number =2section =Arsenal>阿森纳< / page> 
< page number =3section =Arsenal>阿森纳< / page> 
< page number =4section =Arsenal>阿森纳< / page> 
< page number =5section =Arsenal>阿森纳< / page> 
< page number =6section =Arsenal>阿森纳< / page> 
< page number =7section =Chelsea> Chelsea< / page> 
< page number =8section =Chelsea> Chelsea< / page> 
< page number =9section =Chelsea> Chelsea< / page> 
< page number =10section =Chelsea> Chelsea< / page> 
< page number =11section =Chelsea> Chelsea< / page> 
< page number =12section =Chelsea> Chelsea< / page> 
< page number =13section =ManUnited> ManUnited< / page> 
< page number =14section =ManUnited> ManUnited< / page> 
< page number =15section =ManUnited> ManUnited< / page> 
< page number =16section =ManUnited> ManUnited< / page> 
< page number =17section =ManUnited> ManUnited< / page> 
< page number =18section =ManUnited> ManUnited< / page> 
< page number =19section =ManCity> ManCity< / page> 
< page number =20section =ManCity> ManCity< / page> 
< page number =21section =ManCity> ManCity< / page> 
< page number =22section =ManCity> ManCity< / page> 
< page number =23section =ManCity> ManCity< / page> 
< page number =24section =ManCity> ManCity< / page> 
< / root> 
  

输出：

 < TR>< TD→1< / TD>< TD>阿森纳< / TD>< TD→6< / TD>< / TR> 
< tr>< td> 7< / td>< td>切尔西< / td>< td> 12< / td>< / tr> 
< tr>< td> 13< / td>< td> ManU< / td>< td> 18< / td>< / tr> 
< tr>< td> 19< / td>< td> Mancity< / td>< td> 24< / td>< / tr> 
  

解决方案

使用：

 < xsl：stylesheet version =1.0xmlns：xsl =http://www.w3.org/1999/XSL/Transform> 
  
< xsl：key name =kmatch =pageuse =@ section/> 
 
< xsl：template match =/ root> 
< table> 
 < / table> 
< / xsl：template> 
 
< xsl：template match =page> 
< tr> 
< td> 
< xsl：value-of select =@ number/> 
< / td> 
< td> 
< xsl：value-of select =。/> 
< / td> 
< td> 
< xsl：value-of select =key（'k'，@section）[last（）] / @ number/> 
< / td> 
< / tr> 
< / xsl：template> 
< / xsl：stylesheet> 
  

输出：

 <表> 
< tr> 
< td> 1< / td> 
< td>阿森纳< / td> 
< td> 6< / td> 
< / tr> 
< tr> 
< td> 7< / td> 
< td>切尔西< / td> 
< td> 12< / td> 
< / tr> 
< tr> 
< td> 13< / td> 
< td> ManUnited< / td> 
< td> 18< / td> 
< / tr> 
< tr> 
< td> 19< / td> 
< td> ManCity< / td> 
< td> 24< / td> 
< / tr> 
< / table> 
  

Following up on my xslt question from yesterday, link found below.

first last element 2nd variation

I have to output the the first and last page number of each section into a table.

I'm puzzled on where to start. The XSLT 1.0 Solution and XSLT 2.0 Solution would be much appreciated. I would really appreciate any given help.

Regards JJ.

INPUT:

<root>
  <page number="1" section="Arsenal">Arsenal</page> 
  <page number="2" section="Arsenal">Arsenal</page> 
  <page number="3" section="Arsenal">Arsenal</page> 
  <page number="4" section="Arsenal">Arsenal</page> 
  <page number="5" section="Arsenal">Arsenal</page> 
  <page number="6" section="Arsenal">Arsenal</page> 
  <page number="7" section="Chelsea">Chelsea</page> 
  <page number="8" section="Chelsea">Chelsea</page> 
  <page number="9" section="Chelsea">Chelsea</page> 
  <page number="10" section="Chelsea">Chelsea</page> 
  <page number="11" section="Chelsea">Chelsea</page> 
  <page number="12" section="Chelsea">Chelsea</page> 
  <page number="13" section="ManUnited">ManUnited</page> 
  <page number="14" section="ManUnited">ManUnited</page> 
  <page number="15" section="ManUnited">ManUnited</page> 
  <page number="16" section="ManUnited">ManUnited</page> 
  <page number="17" section="ManUnited">ManUnited</page> 
  <page number="18" section="ManUnited">ManUnited</page> 
  <page number="19" section="ManCity">ManCity</page> 
  <page number="20" section="ManCity">ManCity</page> 
  <page number="21" section="ManCity">ManCity</page> 
  <page number="22" section="ManCity">ManCity</page> 
  <page number="23" section="ManCity">ManCity</page> 
  <page number="24" section="ManCity">ManCity</page> 
 </root>

OUTPUT:

<tr><td>1</td><td>Arsenal</td><td>6</td></tr>
<tr><td>7</td><td>Chelsea</td><td>12</td></tr>
<tr><td>13</td><td>ManU</td><td>18</td></tr>
<tr><td>19</td><td>Mancity</td><td>24</td></tr>

解决方案

Use:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>

  <xsl:key name="k" match="page" use="@section"/>

  <xsl:template match="/root">
    <table>
      <xsl:apply-templates select="page[generate-id() = generate-id(key('k', @section))]"/>
    </table>
  </xsl:template>

  <xsl:template match="page">
    <tr>
      <td>
        <xsl:value-of select="@number"/>
      </td>
      <td>
        <xsl:value-of select="."/>
      </td>
      <td>
        <xsl:value-of select="key('k', @section)[last()]/@number"/>
      </td>
    </tr>
  </xsl:template>
</xsl:stylesheet>

Output:

<table>
  <tr>
    <td>1</td>
    <td>Arsenal</td>
    <td>6</td>
  </tr>
  <tr>
    <td>7</td>
    <td>Chelsea</td>
    <td>12</td>
  </tr>
  <tr>
    <td>13</td>
    <td>ManUnited</td>
    <td>18</td>
  </tr>
  <tr>
    <td>19</td>
    <td>ManCity</td>
    <td>24</td>
  </tr>
</table>

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