使用JSP检索和显示来自服务器的图像 [英] Retrieving and displaying image from server using JSP

问题描述

我有一段代码可以帮助我将图像保存在服务器上。我需要知道如何在div上显示保存的图片。

JSP CODE：

 <％String saveFile =; 
 String contentType = request.getContentType（）;如果（（contentType！= null）&& amp;（contentType.indexOf（multipart / form-data）> = 0））{
 DataInputStream in = new DataInputStream（request.getInputStream ））; 
 int formDataLength = request.getContentLength（）; 
字节dataBytes [] =新字节[formDataLength]; 
 int byteRead = 0; 
 int totalBytesRead = 0; 
 while（totalBytesRead< formDataLength）{
 byteRead = in.read（dataBytes，totalBytesRead，formDataLength）; 
 totalBytesRead + = byteRead; 
} 
 String file = new String（dataBytes）; 
 saveFile = file.substring（file.indexOf（filename = \）+ 10）; 
 saveFile = saveFile.substring（0，saveFile.indexOf（\\\
））; 
 saveFile = saveFile.substring（saveFile.lastIndexOf（\\）+ 1，saveFile.indexOf（\））; 
 int lastIndex = contentType.lastIndexOf（=）; 
 String boundary = contentType.substring（lastIndex + 1，contentType.length（））; 
 int pos; 
 pos = file.indexOf（filename = \）; 
 pos = file.indexOf（\ n，pos）+ 1; 
 pos = file.indexOf（ \\\
，pos）+ 1; 
 pos = file.indexOf（\ n，pos）+ 1; 
 int boundaryLocation = file.indexOf（boundary，pos） -  4; 
 int startPos =（（file.substring（0，pos））。getBytes（））。length; 
 int endPos =（（file.substring（0，boundaryLocation））。getBytes（））。文件f =新文件（saveFile）; 
 FileOutputStream fileOut = new FileOutputStream（f）; $ b $ （）; 
 fileOut.close（）; 
}％> 
  code $> 




解决方案

  fileName = new File（D： /../ images /+ saveFile;）。getName（）; 
  

使用这个变量来获得名称，然后在您的img src中调用fileName。希望这有助于。

I have certain piece of code which helps me to save the image on server. I need to know how to display the saved image on div.

JSP CODE:

<%String saveFile="";
String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
saveFile="D:/../images/"+saveFile;
File f = new File(saveFile);
FileOutputStream fileOut = new FileOutputStream(f);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
}%>

解决方案

 fileName = new File("D:/../images/"+saveFile;).getName();

use this variable to get name and then call fileName in your img src. Hope this helps.

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