在jquery函数中发送一个php页面的值 [英] Take a value in php page sent with jquery function
问题描述
在脚本开始的这个html页面中，我在php页面发送变量fin的值（ http://sat3.altervista.org/index.php?valore= + fin）。在这个php页面中，我试图采用变量的值，但是我没有成功。帮助我吗？
$ b $ pre $ <！doctype html>
< html>
< head>
< title>解析< / title>
< script type =text / javascriptsrc =jquery-2.1.0.min.js>< / script>
< / head>
< script>
var fin =SAT000000002575;
url =http://sat3.altervista.org/index .php？valore =+ fin，
data = {
get_param：'value'
};
$ .getJSON （url，data，function（data）{
for（var i = 0; i< data.length; i ++）{
var lin = data [i] [Nr SAT];
$（'body'）。append（$（'< p>）。html（'Numero Sat：< a href =http://sat3.altervista.org/NuovoFile.html?id='+ lin +''>'+ data [i] [Nr SAT] +'< / a>'））; （数据Apertura：'+ data [i] [Data Apertura]））;
$（'body'）。append（$（'< p>
}
}）;
< / script>
< body>
< header>
< / header>
< / body>
< / html>
这是php页面：
<？php
// Sopprimo gli errori del php
error_reporting（0）;
// includo la libreria
require_once'excel_reader2.php';
$ file_handle = fopen（leggimi2.csv，r）;
//编辑：定义一个数组来保存各个行
$ data = array（）;
while（！feof（$ file_handle））{
//这里我拿了这个值，但它不包含任何
$ myValue = $ _GET [ valore];
$ line_of_text = fgetcsv（$ file_handle，1024）;
if（$ line_of_text [0] == $ myValue）
{
$ arr = array（'Nr SAT'=> $ line_of_text [0]，'Data Apertura'=> $ line_of_text [13]，'Tipo Servizio'=> $ line_of_text [1]，'Stato SAT'=> $ line_of_text [2]，'Marca Terminale'=> $ line_of_text [4]，'Modello Terminale'= > $ line_of_text [5]，'IMEI guasto'=> $ line_of_text [6]，'IMEI consegnato'=> $ line_of_text [7]，'Famiglia guasto'=> $ line_of_text [8]'Descrizione guasto '=> $ line_of_text [9]）;
//编辑：将行添加到数组
$ data [] = $ arr;
}
}
//编辑：将数组编码为JSON数组对象
echo json_encode（$ data）;
// $ myValue = isset（$ _ GET ['myValue']）？ $ _GET ['myValue']：'';
fclose（$ file_handle）;
？>
jQuery参考 http://api.jquery.com/jQuery.getJSON/ 表示
的第二个参数是 A用这个请求发送给服务器的纯对象或字符串。
试试这个：
< script type =text / javascript>
var fin =SAT000000002575，
url =http://sat3.altervista.org/index.php，
getVars = {
valore：fin
};
$ .getJSON（url，getVars，function（data）{
//其余代码
}）;
< / script>
并让我们知道：）
编辑
关于你的PHP代码，你必须把这个 $ myValue = $ _GET [valore]; 在您的之前开始。
In this html page at the begin of the script i send the value of variable fin at the php page (http://sat3.altervista.org/index.php?valore="+ fin). In this php page i tried to take the value of variable but i didn't have success. Someone can help me?
<!doctype html>
<html>
<head>
<title>Parsing</title>
<script type="text/javascript" src="jquery-2.1.0.min.js"></script>
</head>
<script>
var fin = "SAT000000002575";
url = "http://sat3.altervista.org/index.php?valore="+ fin,
data = {
get_param: 'value'
};
$.getJSON(url, data, function (data) {
for (var i = 0; i < data.length; i++) {
var lin = data[i]["Nr SAT"];
$('body').append($('<p>').html('Numero Sat: <a href ="http://sat3.altervista.org/NuovoFile.html?id=' + lin + '">' + data[i]["Nr SAT"] + '</a>'));
$('body').append($('<p>').html('Data Apertura: ' + data[i]["Data Apertura"]));
}
});
</script>
<body>
<header>
</header>
</body>
</html>
This is the php page:
<?php
// Sopprimo gli errori del php
error_reporting(0);
// Includo la libreria
require_once 'excel_reader2.php';
$file_handle = fopen("leggimi2.csv", "r");
//EDIT: Define an array to hold individual lines
$data = array();
while (!feof($file_handle) ) {
//HERE I TAKE THE VALUE BUT IT DON'T CONTAIN NOTHING
$myValue = $_GET["valore"];
$line_of_text = fgetcsv($file_handle, 1024);
if ($line_of_text[0] == $myValue)
{
$arr = array('Nr SAT' => $line_of_text[0],'Data Apertura' => $line_of_text[13], 'Tipo Servizio' => $line_of_text[1], 'Stato SAT' => $line_of_text[2],'Marca Terminale' => $line_of_text[4], 'Modello Terminale' => $line_of_text[5], 'IMEI guasto' => $line_of_text[6],'IMEI consegnato' => $line_of_text[7],'Famiglia guasto' => $line_of_text[8],'Descrizione guasto' => $line_of_text[9] );
//EDIT: Add the line to the array
$data[] = $arr;
}
}
//EDIT: Encode the array as a JSON array of line objects
echo json_encode($data);
//$myValue = isset($_GET['myValue']) ? $_GET['myValue'] : '';
fclose($file_handle);
?>
jQuery reference here http://api.jquery.com/jQuery.getJSON/ says that second argument is "A plain object or string that is sent to the server with the request."
Try this:
<script type="text/javascript">
var fin = "SAT000000002575",
url = "http://sat3.altervista.org/index.php",
getVars = {
valore : fin
};
$.getJSON(url, getVars, function(data) {
// rest of your code
});
</script>
And let us know :)
EDIT
Regarding your PHP code, you have to put this $myValue = $_GET["valore"]; before your while begins.
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