当我在外面点击时如何隐藏DIV元素 [英] How to hide a DIV element when I click outside
问题描述
我有一个 div
,想在外面点击时隐藏它。我的代码是:
< div id =mydiv> div必须位于按钮上方< / div>
$ b $('#mydiv')。click(function(e){
e.stopPropagation();
});
$(document).click(function(){
$('#mydiv')。fadeOut(300);
});
但它不适合我...
更新
完整代码如下。当我点击一个按钮时,它会显示上面的 div
,所以当我在外面点击时,我需要隐藏这个 div
。
< div id =butstyle =text-align:right;>< button type =button>显示Div!< / button> ;< / DIV>
< div id =mydivstyle =display:none;> div必须位于按钮上方< / div>
$(#but button)。click(function(){
var pos = $(this).offset(),
div = $(#mydiv );
//在页面外显示所以
//我们可以测量它
div.css({
display:block ,
border:1px纯黑,
position:absolute,
left:-10000,
top:0
});
//将它移动到我们想要的位置
div.css({
left:pos.left - 40,
top:pos.top - div.height() - 10
});
});
$ b $('#myDiv')。click(function(e){
e.stopPropagation();
});
$(document).click(function(){
$('#mydiv')。fadeOut(300);
});
在javascript 中点击 冒泡事件,它始于 div 并转到文档即可。当您使用 stopPropagation()
函数停止事件传播时,不处理单击文档。因此,要解决您的问题,只需删除 e.stopPropagation()
。
最好的方法是:
$('#mydiv')。click(function(e){
e.stopPropagation();
$(this) .fadeOut(300);
});
如果我点击这个div,如何让点击外部并隐藏这个div
$ b好吧,让我们想象一下,当你点击一个id为wrapperId的容器时,myDiv应该隐藏:
$(#wrapperId)。click(function(e){
$('# mydiv')。fadeout(300);
})
如果容器是一个文档,你可以使用
$(document)
而不是$(#wrapperId)
。
它无法正常工作: jsbin.com/ilowij/ 7
单击按钮时应停止单击事件传播。进行这些更改:
$(#but button)。click(function(e){
e。 stopPropagation();
...
}
I have a
div
and want to hide it when I click outside. My code is:<div id="mydiv">The div must be above button</div> $('#mydiv').click(function(e) { e.stopPropagation(); }); $(document).click(function() { $('#mydiv').fadeOut(300); });
But it is not working for me ...
UPDATE
Full code is presented below. When I click on a button it shows a
div
above, so I need to hide thisdiv
when I click outside.<div id="but" style="text-align: right;"><button type="button">Show Div!</button></div> <div id="mydiv" style="display:none;">The div must be above button</div> $("#but button").click(function(){ var pos = $(this).offset(), div = $("#mydiv"); // Make it visible off-page so // we can measure it div.css({ "display": "block", "border": "1px solid black", "position": "absolute", "left": -10000, "top": 0 }); // Move it where we want it to be div.css({ "left": pos.left - 40, "top": pos.top - div.height() - 10 }); }); $('#myDiv').click(function(e) { e.stopPropagation(); }); $(document).click(function() { $('#mydiv').fadeOut(300); });
解决方案In javascript click is a bubbling event, it starts on a div and goes up to a document. When you stop an event propagation using a
stopPropagation()
function, a click on the document is not handled. So, to solve your problem just removee.stopPropagation()
.The best way is:
$('#mydiv').click(function(e) { e.stopPropagation(); $(this).fadeOut(300); });
If I click on this div, how to make to click outside and hide this div ?
Ok, let's imagine, that when you are clicking on a container with id "wrapperId", "myDiv" should be hidden:
$("#wrapperId").click(function(e){ $('#mydiv').fadeOut(300); })
if container is a document, you can use
$(document)
instead of$("#wrapperId")
.It is not working look what is happening: jsbin.com/ilowij/7
You should stop a click event propagation when you are clicking the button. Make these changes:
$("#but button").click(function(e){ e.stopPropagation(); ... }
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