PHP的回声标签，因此它是可见的（不解释为代码） [英] php echo html tag so it is viewable (not interpreted as code)

问题描述

我目前正试图从包含html样式标记的变量中回显文本值。 < ...>

I am currently trying to echo a text value from a variable which contains html-style tags. <...>

$string = "variable_name";
$tag_str = "<".$string.">";
echo $tag_str;

目前这个回声没有像它认为的那样是html代码。我该如何回应< variable_name> 到页面，使其可见，而不是浏览器解释为代码？

currently this echo's as nothing as it believes it is html code. How would I go about echoing <variable_name> to the page so it is viewable and not interpreted as code by the browser?

推荐答案

您必须对您的输出进行html编码

You'll have to html encode your output

$string = "variable_name";
$tag_str = "<".$string.">";
echo htmlspecialchars($tag_str);

这篇关于PHP的回声标签，因此它是可见的（不解释为代码）的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！