Android的获取和分析谷歌路线 [英] android get and parse Google Directions

问题描述

谷歌路线API

我阅读本指南，现在我可以建立一个正确的请求接收XML文件containg从地址A的方向来解决B.我需要的是如何读这个XML绘制获得的一个方向一些指令和示例Android的图形页面。我也想知道重新presents在XML这个标签：

I read this guide now I can build a correct request to receive the xml file containg the directions from address A to address B. What I need is some instructions and example on how to read this xml to draw the obtained directions on an Android MapView. I'd like also to know what represents this tag in the xml:

<overview_polyline>
<points>
a~l~Fjk~uOnzh@vlbBtc~@tsE`vnApw{A`dw@~w\|tNtqf@l{Yd_Fblh@rxo@b}
@xxSfytAblk@xxaBeJxlcBb~t@zbh@jc|Bx}C`rv@rw|@rlhA~dVzeo@vrSnc}Axf]fjz@
xfFbw~@dz{A~d{A|zOxbrBbdUvpo@`cFp~xBc`Hk@nurDznmFfwMbwz@bbl@lq~@lo
Ppxq@bw_@v|{CbtY~jGqeMb{iF|n\~mbDzeVh_Wr|Efc\x`Ij{kE}mAb~uF{cNd}xBjp]
fulBiwJpgg@|kHntyArpb@bijCk_Kv~eGyqTj_|@`uV`k|DcsNdwxAott@r}q@_gc@nu`CnvH
x`k@dse@j|p@zpiAp|gEicy@`omFvaErfo@igQxnlApqGze~AsyRzrjAb__@ftyB}pIlo_B
flmA~yQftNboWzoAlzp@mz`@|}_@fda@jakEitAn{fB_a]lexClshBtmqAdmY_hLxiZd~XtaBndgC
</points>
<levels>BBBAAAAABAABAAAAAABBAAABBAAAABBAAABABAAABABBAABAABAAAABABABABBABAABB</levels> 
</overview_polyline> 

感谢

推荐答案

我发现这个例子中，网页，我会尝试使用它。 <一href="http://jeffreysambells.com/posts/2010/05/27/decoding-polylines-from-google-maps-direction-api-with-java/">polyline解码例如

I found this example on the web I'll try to use it. polyline decoding example

private List<GeoPoint> decodePoly(String encoded) {

  List<GeoPoint> poly = new ArrayList<GeoPoint>();
  int index = 0, len = encoded.length();
  int lat = 0, lng = 0;

  while (index < len) {
      int b, shift = 0, result = 0;
      do {
          b = encoded.charAt(index++) - 63;
          result |= (b & 0x1f) << shift;
          shift += 5;
      } while (b >= 0x20);
      int dlat = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
      lat += dlat;

      shift = 0;
      result = 0;
      do {
          b = encoded.charAt(index++) - 63;
          result |= (b & 0x1f) << shift;
          shift += 5;
      } while (b >= 0x20);
      int dlng = ((result & 1) != 0 ? ~(result >> 1) : (result >> 1));
      lng += dlng;

      GeoPoint p = new GeoPoint((int) (((double) lat / 1E5) * 1E6),
           (int) (((double) lng / 1E5) * 1E6));
      poly.add(p);
  }

  return poly;
}

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