使用XSLT将XML分割成多个HTML文件 [英] Split XML into multiple HTML files using XSLT

问题描述

一个例子xml：

p>

An example xml:

<?xml version="1.0" encoding="ISO-8859-1"?>

<table>
  <row>
    <name>user1</name>
    <email>email1</email>
  </row>
  <row>
    <name>user2</name>
    <email>email2</email>
  </row>
  <row>
   <name>user3</name>
   <email>email3</email>
  </row>
  <row>
    <name>user4</name>
    <email>email4</email>
  </row>
  <row>
    <name>user5</name>
    <email>email5</email>
  </row>

  ...

</table>

现在我想将这个xml文件分成不同的HTML文件，这些文件包含XML文件中特定的范围。例如，每个HTML文件应该包含来自XML的3行。

Now I want to split this xml file into different HTML files which contain a specific range from the XML file. Each HTML file should contain 3 rows from the XML for example.

table1.html

<table>
  <tr>
    <td>user1</td>
    <td>email1</td>
  </tr>
  <tr>
    <td>user2</td>
    <td>email2</td>
  </tr>
  <tr>
    <td>user3</td>
    <td>email3</td>
  </tr>
</table>

table2.html

<table>
  <tr>
    <td>user4</td>
    <td>email4</td>
  </tr>
  <tr>
    <td>user5</td>
    <td>email5</td>
  </tr>
  <tr>
    <td>user6</td>
    <td>email6</td>
  </tr>
</table>

任何人都知道XSLT文件需要如何格式化？我使用 ruby​​-xslt 加载XML和XSLT文件，并将整个事件转换为HTML 。

Anyone an idea how the XSLT file needs to be formatted? I'm using ruby-xslt to load the XML and XSLT file and convert the whole thing to HTML.

推荐答案

如果您将此XSLT应用于您的输入XML，它会将XML分成包含3条记录的表：

If you apply this XSLT to your input XML it will split the XML into tables containing 3 records:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:strip-space elements="*"/>
<xsl:output indent="yes" method="xml"/>

<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>
<!-- split file up into row elements -->
<xsl:template match="row[position() mod 3 = 1]">
    <table>
        <xsl:copy-of select=".|following-sibling::row[not(position() > 2)]"/>
    </table>
</xsl:template>

<xsl:template match="row"/>
</xsl:stylesheet>

输出XML：

OUTPUT XML:

<?xml version="1.0" encoding="UTF-8"?>
<table>
<table>
    <row>
        <name>user1</name>
        <email>email1</email>
    </row>
    <row>
        <name>user2</name>
        <email>email2</email>
    </row>
    <row>
        <name>user3</name>
        <email>email3</email>
    </row>
</table>
<table>
    <row>
        <name>user4</name>
        <email>email4</email>
    </row>
    <row>
        <name>user5</name>
        <email>email5</email>
    </row>
</table>
</table>

如果您通过此XSLT运行OUTPUT XML，您将得到想要的结果：

If you run the OUTPUT XML through this XSLT you will get the wanted result:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">

<xsl:template match="node()|@*">
    <xsl:copy>
        <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="row">
    <tr>
        <xsl:apply-templates select="node()|@*"/>
    </tr>
</xsl:template>

<xsl:template match="email | name">
    <td>
        <xsl:apply-templates select="node()|@*"/>
    </td>
</xsl:template>


</xsl:stylesheet>

final OUTPUT XML：

final OUTPUT XML:

    <?xml version="1.0" encoding="UTF-8"?><table>
<table>
    <tr>
        <td>user1</td>
        <td>email1</td>
    </tr>
    <tr>
        <td>user2</td>
        <td>email2</td>
    </tr>
    <tr>
        <td>user3</td>
        <td>email3</td>
    </tr>
</table>
<table>
    <tr>
        <td>user4</td>
        <td>email4</td>
    </tr>
    <tr>
        <td>user5</td>
        <td>email5</td>
    </tr>
</table>
</table>

在我看来，只要您有机会运行2个样式表，就可以使用XSLT 1.0您的输入XML。

In my opinion this should work with XSLT 1.0 as long as you have the opportunity to run 2 stylesheets on your input XML.

祝好，
彼得

这篇关于使用XSLT将XML分割成多个HTML文件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！