每个表单的每个Radibutton或所有单选按钮的1个表单？ [英] Each Radiobutton for each form or 1 Form for all radiobuttons?

问题描述

我在这个主页上遇到了问题。

我必须创建一个这样的网站：

  status创建工作完成
 
 Item1 * oo 
 Item2 o * o 
 Item3 oo * 
  

（* =已勾选，o =未勾选）

现在作为管理员，我有权改变每个项目的状态。

例如，当我将状态从Item1更改为work时，它应该发送一个Form并将其更新到Database中。

我的问题是知道的，我应该为每对3个单选按钮创建1个表单吗？

但是当我创建1所有按钮我都会有问题知道哪些状态发生了变化。

仅与每个数据库条目进行比较。

在有人问我之前，我应该使用单选按钮。
希望有人可以帮忙。

Greetz

恶魔

编辑：对不起，eomeone误解了我。
我的意思是如果我会更快更好：

 < form method =post> 
 Item 1< input type =radioname =item1value =createonclick =this.form.submit（）/> 
< input type =radioname =item1value =workonclick =this.form.submit（）/> 
< input type =radioname =item1value =finishedonclick =this.form.submit（）/> 
< / form> 
 
< form method =post> 
 Item 2< input type =radioname =item2value =createonclick =this.form.submit（）/> 
< input type =radioname =item2value =workonclick =this.form.submit（）/> 
< input type =radioname =item2value =finishedonclick =this.form.submit（）/> 
< / form> 
  

或

 < form method =post> 
 Item 1< input type =radioname =item1value =createonclick =this.form.submit（）/> 
< input type =radioname =item1value =workonclick =this.form.submit（）/> 
< input type =radioname =item1value =finishedonclick =this.form.submit（）/> 
 Item 2< input type =radioname =item2value =createonclick =this.form.submit（）/> 
< input type =radioname =item2value =workonclick =this.form.submit（）/> 
< input type =radioname =item2value =finishedonclick =this.form.submit（）/> 
 
 
< / form> 
  

因为PHP / MySQL的性能

解决方案

我可能会使用一个表单，然后为所有值执行数据库更新。

然后我会使用javascript来扩充页面，即保留它为不支持/执行javascript但具有仅发送已执行javascript的客户端中已更改的值的提交处理程序的客户端工作。

然后，我会执行一些基准测试/分析以检查如果仅更改值版本确实比更新所有值版本更快/更好。如果不是javascript部分是历史; - ）

i have a problem with this homepage.

I have to create a Site like this:

status   create work finished

Item1    *       o      o
Item2    o       *      o
Item3    o       o      *

(* = checked, o = unchecked)

Now as admin i have the rights to change the status of the each Item.

For example when i change the Status from Item1 to "work" it should send a Form and update it in Database.

My Problem is know, should i create for each pair of 3 radiobuttons 1 Form?

But when i create 1 for all Buttons i will have problems to know which status have changed.
Only compare with each Database entry.

Before someone ask, i should use radiobuttons. Hope someone could help.

Greetz

Demonking

Edit: Sorry, eomeone have misunderstand me. I meant if i would be faster and better with :

<form method="post">
 Item 1 <input type="radio" name="item1" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="finished" onclick="this.form.submit()"/>
</form>

<form method="post">
 Item 2 <input type="radio" name="item2" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="finished" onclick="this.form.submit()"/>
</form>

or

<form method="post">
 Item 1 <input type="radio" name="item1" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item1" value="finished" onclick="this.form.submit()"/>
 Item 2 <input type="radio" name="item2" value="create" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="work" onclick="this.form.submit()"/>
 <input type="radio" name="item2" value="finished" onclick="this.form.submit()"/>


</form>

because of Performance with PHP/MySQL

解决方案

I'd probably use one form and then perform a database update for all values.
And then I'd use javascript to augment the page, i.e. keep it working for clients that don't support/execute javascript but have a submit-handler that only sends values that have changed in clients that do execute javascript.
And then I'd do some benchmarking/profiling to check if the "only changed values" versionn really is faster/better than the "update all values" version. If not the javascript part is history ;-)

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