在Table中显示ajax响应 [英] Display ajax response in Table
问题描述
display.html:
< div id =display_resultstyle =display:none>< table class =table>
< thead>
< tr>
< th> Die No< / th>
< th>状态< / th>
< th>位置< / th>
< th>选择< / th>
< / tr>
< / thead>
< tbody>
< / table>
< div id =issue_button>
< input type =submitid =submitclass =btn btn-successvalue =Recievestyle =width:150px;>< / div>
< / div>
Ajax:
var data = JSON.stringify($(#form)。serializeArray());
// alert(data);
$ .ajax({//在POST中使用Ajax将证书值发送到另一个checker.php menthod
类型:'POST',
data:{
list:data
},
url:'die_recieving_process.php',
success:function(data)){
$('#display_result')。html(data);
}
});
die_recieving_process.php
while($ fetch = mysql_fetch_array($ query))
{
if($ fetch [1] ==Table Rack)
{
echo '< tr class =success>< td>'。$ fetch [0]。'< / td>< td>'。 ;'。$ fetch [3]。 < / TD> < td>< input type = checkbox class =chkid = check_box value ='。$ fetch [2]。'name = check_list []< / td> < / TR>;
}
else
{
echo'< tr class =warning>< td>。$ fetch [0]。'< / td><< ; td>'。$ fetch [1]。'< / td>< td>'。$ fetch [3]。 < / TD> < td>< input type = checkbox class =chkid = check_box value ='。$ fetch [2]。'name = check_list [] checked< / td> < / TR>;
$ / code $ / pre
你好朋友在display.html我必须显示结果在die_recieving_process.php中处理。在ajax中,我将所有的值发送到die_recieving_process.php,并在获取结果后,将结果显示在display.html中。
解决方案 在你的JavaScript中,你有2个错误:
你的代码覆盖div的现有内容,这是整个表...
你有一个不必要的在成功函数声明中支架
所以改变这个:
pre $ 成功:函数(数据)){
$('#display_result')。html(data);
}
至此:
success:function(data){//移除不必要的括号
$('#display_result tbody')。html(data); //将数据添加到tbody,而不是div
}
顺便说一句,使用 $。post()你可以编写较短的JavaScript代码,如下所示:
var data = JSON.stringify($(#form)。serializeArray());
$ .post('die_recieving_process.php',{list:data},function(responseData){
$('#display_result tbody')。html(responseData); //添加到tbody中,里面#display_result
$('#display_result')。show();
});
第二您需要关闭表格中的tbody标记
display.html :
<div id="display_result" style="display: none"><table class="table">
<p style="float: right;" >Select All<input type="checkbox" class="allcb" data-child="chk" checked/> </p>
<thead>
<tr>
<th>Die No</th>
<th> Status </th>
<th> Location </th>
<th>Select</th>
</tr>
</thead>
<tbody>
</table>
<div id ="issue_button">
<input type="submit" id="submit" class="btn btn-success " value="Recieve" style="width: 150px;"></div>
</div>
Ajax:
var data = JSON.stringify($("#form").serializeArray());
// alert(data);
$.ajax({ // Send the credential values to another checker.php using Ajax in POST menthod
type: 'POST',
data: {
list: data
},
url: 'die_recieving_process.php',
success: function(data) ){
$('#display_result').html(data);
}
});
die_recieving_process.php
while($fetch = mysql_fetch_array($query))
{
if($fetch[1] == "Table Rack" )
{
echo '<tr class="success"><td>'.$fetch[0].'</td><td>'.$fetch[1].'</td><td>'.$fetch[3] . '</td> <td><input type=checkbox class="chk" id=check_box value= '.$fetch[2].' name= check_list[] </td> </tr>';
}
else
{
echo '<tr class="warning"><td>'.$fetch[0].'</td><td>'.$fetch[1].'</td><td>'.$fetch[3] . '</td> <td><input type=checkbox class="chk" id=check_box value= '.$fetch[2].' name= check_list[] checked </td> </tr>';
}
}
Hi friends in display.html I have to display the result processed in die_recieving_process.php . In ajax i've sent all the value to die_recieving_process.php and after fetching the result i've to display the result in display.html
First in you Javascript, you have 2 errors: Your code overrides existing contents of div, which is the whole table... And you have one unnecessary bracket in success function declaration
So change this:
success: function(data) ){
$('#display_result').html(data);
}
To this:
success: function(data) {//remove unnecessary bracket
$('#display_result tbody').html(data);//add data - to tbody, and not to the div
}
By the way, using $.post() you can write your javascript code shorter, like this:
var data = JSON.stringify($("#form").serializeArray());
$.post('die_recieving_process.php',{list:data},function(responseData){
$('#display_result tbody').html(responseData); //added to tbody which is inside #display_result
$('#display_result').show();
});
Second you need to close your tbody tag inside the table
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