从servlet内部调用外部站点时获取HTTP 406 [英] Getting HTTP 406 while calling external site from within servlet

问题描述

  / ** 
 * @see HttpServlet＃doPost（ HttpServletResponse响应）
 * @see HttpServlet＃doGet（HttpServletRequest请求，HttpServletResponse响应）
 * / $ b $ public void doIt（HttpServletRequest请求，HttpServletResponse响应）抛出ServletException，IOException {
 
 URL url = new URL（http://some.url.that.works.well.nl/q=hello&ie=nl&cx=hdyehgfyegywjehdkwed:7364du7）; 
 
 URLConnection conn = url.openConnection（）; 
 conn.connect（）; 
 
 BufferedReader br = new BufferedReader（
 new InputStreamReader（conn.getInputStream（）））; //此行生成错误
 String line =; 
 PrintWriter pw = response.getWriter（）; （（line = br.readLine（））！= null）{
 pw.println（line）; 
 while 
 
 
 $ / code> 

在tomcat中运行这个servlet会给我一个http 406错误。



我试图做的是从我的servlet中调用google站点搜索，并且我想解析接收到的（XML）结果。 （现在我只是打印收到的结果）。
在浏览器中尝试url会给出正确的结果。

我在这里错过了什么？

亲切的问候，
维尔纳

解决方案

我解决了这个问题。调查通过网络发送的内容。

我的网址包含一个空格，导致了所有问题。

正如前面所述我想联系谷歌搜索，我的网址看起来像这样：

  http://www.google.com/search?q = golden handpressure& ie = 8758438& cx = hjfweufhweufwef：9e 
  

这是在浏览器地址栏但在java中没有。

使用wireshark，我发现我的请求头包含：

 请求URI：http://www.google.com/search?q=golden 
请求版本：handpressure& ie = 8758438& cx = hjfweufhweufwef：9e 
  

这当然不正确。它应该都是一个名为'Request URI'的字段。

将空间改为'％20'解决了这个问题。

I have the following code in my servlet:

/**
 * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
 * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
 */
public void doIt(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    URL url = new URL("http://some.url.that.works.well.nl/q=hello&ie=nl&cx=hdyehgfyegywjehdkwed:7364du7");

    URLConnection conn = url.openConnection();
    conn.connect();

    BufferedReader br = new BufferedReader(
        new InputStreamReader(conn.getInputStream()));  // This line is generating the error
    String line = "";
    PrintWriter pw = response.getWriter();
    while((line = br.readLine()) != null) {
        pw.println(line);
    } 
}

running this servlet in tomcat gives me an http 406 error.

What I try to do is from within my servlet call google site search and I would like to parse the receieved (XML) result. (For now I just print te received result). Trying the url in a browser is giving the correct result.

What am I missing here?

Kind regards, Werner

解决方案

I solved the problem.
I used wireshark to investigate what was send across the wire.
My url contained a space and that was causing all the problems.

As told before I wanted to contact google search and my url looked something like:

http://www.google.com/search?q=golden handpressure&ie=8758438&cx=hjfweufhweufwef:9e

this is working in the browser address bar but not in java.

With wireshark I found out that my request header contained:

Request URI: http://www.google.com/search?q=golden
Request version: handpressure&ie=8758438&cx=hjfweufhweufwef:9e

This is ofcourse not correct. it should all be one field called 'Request URI'.
Changing the space into '%20' solved the problem.

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