如何在不占用空间的情况下将元素相对于另一元素进行定位 [英] How do I position an element relative to another without taking up space
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问题描述
我想在点击元素下方显示一个弹出窗口。
然而,该元素位于其他元素之间。
当我在两个其他元素之间放置弹出窗口并使其位置相对时,它仍然占用空间。
在下面的简化示例中,我想定位'div'下面的'menu',值为'X'。
。图标{font-size:10px;向左飘浮; height:30px;宽度:30px; background-color:#EAEAEA; padding-top:2px; margin-right:3px; border:0px; border-radius:3px;}。v-divider {float:left; height:35px; border:0; border-right:1px solid#d9d6d0; margin:0px 5px 0px 5px;}。menu {position:relative;顶部:40px; margin-bottom:100px;宽度:100px; border:1px solid#a1a1a1; padding:5px;}。block {float:left; margin:7px 0px 5px 0px;}
< div class ='v-divider'>< / div>< div class ='block'> < button type =buttonclass =icon> A< / button> < button class =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>< div class ='block' > < button type =buttonclass =icon> A< / button> < button type =buttonclass =icon> A< / button> < button class =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>< > < div id ='menu'> <跨度>布拉布拉< /跨度> < / div>< / div>< div class ='block'> < button type =buttonclass =icon> X< / button> < button type =buttonclass =icon> A< / button> < button type =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>
解决方案
请检查代码段,你想要相同。
$(.icon).click(function(){var偏移= $(this).position(); console.log(left:+ offset.left +,top:+ offset.top); $(。menu)。css({left: / code>
.icon { font-size:10px;向左飘浮; height:30px;宽度:30px; background-color:#EAEAEA; padding-top:2px; margin-right:3px; border:0px; border-radius:3px;}。v-divider {float:left; height:35px; border:0; border-right:1px solid#d9d6d0; margin:0px 5px 0px 5px;}。menu {position:fixed;顶部:40px; margin-bottom:100px;宽度:100px; border:1px solid#a1a1a1;填充:5px; margin-top:10px;}。block {float:left; margin:7px 0px 5px 0px;}
< script src =https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js>< / script>< div class ='v-divider'>< / div>< div class ='block'> < button type =buttonclass =icon> A< / button> < button class =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>< div class ='block' > < button type =buttonclass =icon> A< / button> < button type =buttonclass =icon> A< / button> < button class =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>< > < div id ='menu'> <跨度>布拉布拉< /跨度> < / div>< / div>< div class ='block'> < button type =buttonclass =icon> X< / button> < button type =buttonclass =icon> A< / button> < button type =buttonclass =icon> A< / button>< / div>< div class ='v-divider'>< / div>
I'd like to show a popup, when clicked, underneath the clicked element. This element however is positioned between other elements. When I place the popup between 2 other elements and make it position relative, it still takes up space.
In below simplified example I'd like to position the 'menu' underneath the div with the value 'X'.
.icon {
font-size: 10px;
float: left;
height: 30px;
width: 30px;
background-color: #EAEAEA;
padding-top: 2px;
margin-right: 3px;
border: 0px;
border-radius: 3px;
}
.v-divider {
float: left;
height: 35px;
border: 0;
border-right: 1px solid #d9d6d0;
margin: 0px 5px 0px 5px;
}
.menu {
position: relative;
top: 40px;
margin-bottom: 100px;
width: 100px;
border: 1px solid #a1a1a1;
padding: 5px;
}
.block {
float: left;
margin: 7px 0px 5px 0px;
}
<div class='v-divider'></div>
<div class='block'>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
<div class='block'>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
<div class='menu'>
<div id='menu'>
<span>blabla</span>
</div>
</div>
<div class='block'>
<button type="button" class="icon">X</button>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
解决方案
Please check the snippet, do you want the same.
$( ".icon" ).click(function() {
var offset = $(this).position();
console.log( "left: " + offset.left + ", top: " + offset.top );
$(".menu").css({"left":offset.left});
});
.icon {
font-size: 10px;
float: left;
height: 30px;
width: 30px;
background-color: #EAEAEA;
padding-top: 2px;
margin-right: 3px;
border: 0px;
border-radius: 3px;
}
.v-divider {
float: left;
height: 35px;
border: 0;
border-right: 1px solid #d9d6d0;
margin: 0px 5px 0px 5px;
}
.menu {
position: fixed;
top: 40px;
margin-bottom: 100px;
width: 100px;
border: 1px solid #a1a1a1;
padding: 5px;
margin-top:10px;
}
.block {
float: left;
margin: 7px 0px 5px 0px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class='v-divider'></div>
<div class='block'>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
<div class='block'>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
<div class='menu'>
<div id='menu'>
<span>blabla</span>
</div>
</div>
<div class='block'>
<button type="button" class="icon">X</button>
<button type="button" class="icon">A</button>
<button type="button" class="icon">A</button>
</div>
<div class='v-divider'></div>
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