用于搜索的正则表达式并获取图像的src [英] Regex for search and get the src of a image
本文介绍了用于搜索的正则表达式并获取图像的src的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
...< img class =employee thumbsrc =http：//localhost/services/employee1.jpg /> ...
我想搜索这个标签是否可用，如果是的话，获取src url。 < img class =employee thumb可用于唯一标识标签。
如何在python中执行此操作？
解决方案
使用正则表达式：
>>> import re
>>> str ='< img class =employee thumbsrc =http：//localhost/services/employee1.jpg/>'
>>>如果re.search（'img class =employee thumb'，str）：
... print re.findall（'src =（。*？）'，s，re.DOTALL）
...
['http：//localhost/services/employee1.jpg']
使用lxml：
>>> from lxml import etree
>>> root = etree.fromstring（
...< html>
...< img class =employee thumbsrc =http：//localhost/services/employee1.jpg />
...< / html>
...）
>>> print root.xpath（// img [@ class ='employee thumb'] / @ *）[1]
http：//localhost/services/employee1.jpg
Assume I am having a html string containing the following code snippet.
... <img class="employee thumb" src="http://localhost/services/employee1.jpg" /> ...
I want to search whether this tag is available and if so get the src url. <img class="employee thumb" can be used to uniquely identify the tag.
How to do this in python?
解决方案
Using Regular Expression :
>>> import re
>>> str = '<img class="employee thumb" src="http://localhost/services/employee1.jpg" />'
>>> if re.search('img class="employee thumb"', str):
... print re.findall ( 'src="(.*?)"', s, re.DOTALL)
...
['http://localhost/services/employee1.jpg']
Using lxml :
>>> from lxml import etree
>>> root = etree.fromstring("""
... <html>
... <img class="employee thumb" src="http://localhost/services/employee1.jpg" />
... </html>
... """)
>>> print root.xpath("//img[@class='employee thumb']/@*")[1]
http://localhost/services/employee1.jpg
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