ajax表单不更新值 [英] ajax form not updating values
本文介绍了ajax表单不更新值的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有更新db的用户信息的表单。然而,这个功能不适用于ajax(使用简单的提交刷新)。
这将形式序列化的数据发送到服务器
jQuery
$('#commit-changes')。click(function(){
$('#validation')。submit(function(){
$ .ajax({
type:POST,
data:$(#validation)。serialize (),
cache:false,
url:modules / user / updateuser.php,
success:function(data){
$(#response-update ).html(data);
},
error:function(){
alert(ERROR);
}
});
});
});
以下是输出标记
HTML
$ rcs_roles = $ user-> getRoles();
$ role ='';
foreach($ rcs_roles as $ roles)
{
if($ roles-> role_number == $ rcs_user-> permissao)
$ role。='< option value ='。$ roles-> role_number。'selected =selected>'。$ roles-> role。'< / option>';
else
$ role。='< option value ='。$ roles-> role_number。'>'。$ roles-> role。'< / option>';
}
if($ rcs_user-> activo == 0)
{
$ activo ='< input type =checkboxname =activo class =on_off_checkboxvalue =1/>';
$ activo ='< input type =checkboxname =activoclass =on_off_checkboxchecked =checkedvalue =1 />';
}
$ response ='';
$ response。='< form id =validationaction =method =post>
< fieldset>
< input type =hiddenname =user_id
value ='。$ _ POST ['user_id']。'/>
< legend> Actualizar Dados Utilizador< / legend>
< div class =section>
< label> Nome< small> Insira o seu nome< / small>< / label>
< div>
将。INPUT TYPE = 文本 类= 验证[需要,定制[onlyLetterSp]]大的 名称= 诺姆 ID = f_required 值=函数utf8_encode($ rcs_user->诺姆) '。>
< / div>
< / div>';
$ response。='< div class =section>
< label>电子邮件< small> Insira o seu电子邮件< / small>< / label>
< div>
< input type =textclass =validate [required,custom [email]] largename =emailid =e_requiredvalue ='。utf8_encode($ rcs_user-> email) '。>
< / div>
< / div>';
$ response。='< div class =section>
< label>Permissões< small> Seleccione o tipo de utilizador< / small>< / label>
< div>
< select class =mediumname =role>
'。$ role。'
< / select>
< / div>
< / div>
< div class =section>
< label> Activo< small> Activar utilizador< / small>< / label>
< div>
'。$ activo。'
< span class =f_help> ON / OFF< / span>
< / div>
< / div>
< div class =section last>
< div>
将一个ID = 提交-变化 类= 的UIButton submit_form 名称= 提交 > Gravar< / A><类别= UIButton的特殊 的onClick = ResetForm() 标题= LimparFormulário> LimparFormulário< / a>
< / div>
< / div>
< / fieldset>< / form>';
然后服务器端处理
PHP
$ response ='';
$ id_user = $ _POST ['user_id'];
$ name = utf8_encode($ _ POST ['nome']);
$ email = utf8_encode($ _ POST ['email']);
$ permitions = $ _POST ['role'];
if(!isset($ _ POST ['activo']))
{
$ active = 0;
}
else
{
$ active = 1;
}
$ user = new Users();
尝试
{
$ user-> updateUsers($ name,$ email,$ permitions,$ active,$ id_user);
$ response =SUCESSO;
}
catch(Exception $ e)
{
$ response =ERRO。$ e-> getMessage();
}
echo $ response;
很高兴为您提供所有帮助
updateUsers 函数中(在Users类中),尝试更新字段 nome 或名称?
假设您只使用 nome 正确?
I've got this form that updates user information on db. However, this functionality is not working with ajax (works with a simple submit with refresh).
This postes form serialized data to the server jQuery
$('#commit-changes').click(function(){
$('#validation').submit(function(){
$.ajax({
type: "POST",
data: $("#validation").serialize(),
cache: false,
url:"modules/user/updateuser.php",
success : function(data){
$("#response-update").html(data);
},
error:function(){
alert("ERROR");
}
});
});
});
Here's the HTML that outputs the markup HTML
$rcs_roles = $user->getRoles();
$role ='';
foreach($rcs_roles as $roles)
{
if($roles->role_number == $rcs_user->permissao)
$role .= '<option value="'.$roles->role_number.'" selected="selected">'.$roles->role.'</option>';
else
$role.= '<option value="'.$roles->role_number.'">'.$roles->role.'</option>';
}
if($rcs_user->activo == 0)
{
$activo = '<input type="checkbox" name="activo" class="on_off_checkbox" value="1" />';
}
else
{
$activo = '<input type="checkbox" name="activo" class="on_off_checkbox" checked="checked" value="1" />';
}
$response = '';
$response.='<form id="validation" action="" method="post">
<fieldset >
<input type="hidden" name="user_id"
value="'.$_POST['user_id'].'"/>
<legend>Actualizar Dados Utilizador</legend>
<div class="section ">
<label>Nome<small>Insira o seu nome</small></label>
<div>
<input type="text" class="validate[required,custom[onlyLetterSp]] large" name="nome" id="f_required" value="'.utf8_encode($rcs_user->nome).'">
</div>
</div>';
$response.='<div class="section ">
<label> Email<small>Insira o seu email</small></label>
<div>
<input type="text" class="validate[required,custom[email]] large" name="email" id="e_required" value="'. utf8_encode($rcs_user->email).'">
</div>
</div>';
$response.= '<div class="section">
<label>Permissões<small>Seleccione o tipo de utilizador </small></label>
<div>
<select class="medium" name="role">
'.$role.'
</select>
</div>
</div>
<div class="section">
<label>Activo<small>Activar utilizador</small></label>
<div>
'.$activo.'
<span class="f_help">ON / OFF </span>
</div>
</div>
<div class="section last">
<div>
<a id="commit-changes" class="uibutton submit_form" name="submit" >Gravar</a><a class="uibutton special" onClick="ResetForm()" title="Limpar Formulário" >Limpar Formulário</a>
</div>
</div>
</fieldset></form>';
And then the server side processing PHP
$response='';
$id_user = $_POST['user_id'];
$name = utf8_encode($_POST['nome']);
$email = utf8_encode($_POST['email']);
$permitions = $_POST['role'];
if(!isset($_POST['activo']))
{
$active = 0;
}
else
{
$active = 1;
}
$user = new Users();
try
{
$user->updateUsers($name, $email, $permitions, $active, $id_user);
$response = "SUCESSO";
}
catch (Exception $e)
{
$response = "ERRO".$e->getMessage();
}
echo $response;
Glad for all the help I can get
解决方案
In the updateUsers function (in Users class) you try to update the field nome or name ?
You are suppose to use nome only right?
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