如何使用PHP获取HTML下拉菜单的值？ [英] How to get a value of HTML drop down menu using PHP?

问题描述

我有一个带有一些选项的下拉菜单的HTML脚本。一旦你选择了你的话题，它就会进入我的PHP脚本，名为 process.php 。在 process.php 中，它取得HTML下拉菜单的值并将其写入文件。或者至少这是我想要它做的......

I have a HTML script that has a dropdown menu with some options. Once you have selected your topic it goes to my PHP script called process.php. In that process.php it takes the value of the HTML dropdown menu and writes it to a file. Or at least that is what I want it to do...

以下是我的代码：

<form id="form1" action="process.php" name="form1" method="post"
     <select id="form">
         <option name="--Select_a_Topic--" value="--Select a Topic--">--Select a Topic--</option>
      <option name="Dog" value="Dog">Dog</option>
      <option name="Cat" value="Cat">Cat</option>
      <option name="Other" value="Other">Other</option>
    </select>
</form>

help.php：

help.php:

<?php
if (isset($_POST['form')){
    $topic = $_POST['form'];
    }
$fh = fopen('putithere.txt', 'a');
fwrite($fh, $topic);
fclose('putithere.txt');
?>

PHP错误日志：

PHP error log:

PHP Notice:  Undefined index: form in /Applications/MAMP/htdocs/Website/process.php on line 'whatever'

推荐答案

请尝试以下代码：

Try following code

<form id="form1" action="help.php" name="form1" method="post">
         <select name="pet" id="form">
          <option value="-1">--Select a Topic--</option>
          <option value="Dog">Dog</option>
          <option value="Cat">Cat</option>
          <option value="Other">Other</option>
        </select>
</form>

现在您可以使用 $ _ POST ['pet'] 在php中。
也是一个好主意，将您的默认值设置为 -1

now option that you selected is accessible with $_POST['pet'] in php. also it's a good idea that set your default value to -1

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