在浏览器中显示xml和xslt [英] display xml and xslt in a browser

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问题描述

我有2个文件，file.xml和file.xsl。我正在寻找如何在浏览器中查看结果。从我的研究中，我了解到，只有IE获得了XML解析器，而对于其他浏览器，我需要一个servor脚本。
我也将这些行放在我的xml文件的顶部： 

 <？xml version =1.0 encoding =UTF-8？> 
<？xml-stylesheet type =text / xslhref =Employe.xsl？>

以及我的xsl文件顶部的这些ligne：

 <？xml version =1.0encoding =UTF-8？> 
< xsl：stylesheet version =1.0
 xmlns：xsl =http://www.w3.org/1999/XSL/Transform>

然而，即使我使用IE（11），我也只有文本没有任何风格我已经说了。
我想在表格中显示元素，但没有。



如果有任何我没有找到的错误，我会给你我的表格代码，但通常它是可以的。


$ 

 < xsl：template match =/> 
< html> 
< body> 
 
< h2>工人清单< / h2> 
< table border =1> 
< tr bgcolor =＃9acd32> 
< th rowspan = 3> ID< / th> 
< th colspan = 5>基本信息< / th> 
< th rowspan = 3>图片< / th> 
< th colspan = 2>技能启用< / th> 
< / tr> 
< tr> 
< td rowspan = 2>名称< / td> 
< td colspan = 3>地址< / td> 
< td rowspan = 2>电话号码< / td> 
< td rowspan = 2>技巧1< / td> 
< td rowspan = 2>技巧2< / td> 
< / tr> 
< tr> 
< td>号码< / td> 
< td>街< / td> 
< td>城镇< / td> 
< / tr> 
< xsl：for-each select =List_Of_Employe / Employe> 
< xsl：sort select =Name/> 
< tr> 
< td>< xsl：value-of select =ID/>< / td> 
< td>< xsl：value-of select =Basic_Information / Name/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Number/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Street/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Town/>< / td> 
< td>< xsl：value-of select =Basic_Information / Phone_Number/>< td /> 
< td>< xsl：value-of select =Photo/>< / td> 
< td>< xsl：value-of select =Skills_Enable / Skill_1/>< / td> 
< td>< xsl：value-of select =Skills_Enable / Skill_2/>< / td> 
< / tr> 
< / xsl：for-each> 
< / table> 
< / body> 
< / html> 
< / xsl：template> 
 
< / xsl：stylesheet>

以下是我的xml代码： 

 < List_Of_Employe> 
 
 
 
< Employe> 
 
< ID> 1235< / ID> 
 
< Basic_Information> 
 
<名称>詹姆斯邦德< / Name> 
 
<地址> 
< Number> 05< / Number> 
<街>皇后街< / Street> 
<城市>伦敦< / Town> 
< /地址> 
 
< Phone_Number> 07876543210< /电话号码> 
 
< /基本信息> 
 
<图片> James.png< /照片> 
 
< Skills_Enable> 
< Skill_1> XML< / Skill_1> 
< Skill_2> C＃< / Skill_2> 
< / Skills_Enable> 
 
< /雇主> 
 
< Employe> 
 
< ID> 1236< / ID> 
 
< Basic_Information> 
 
<名称>夏洛克福尔摩斯< / Name> 
 
<地址> 
< Number> 100< / Number> 
<街>王子街< / Street> 
<城市>伦敦< / Town> 
< /地址> 
 
< Phone_Number> 07765432100< / Phone_Number> 
 
< /基本信息> 
 
<图片> Sherlock.png< /照片> 
 
< Skills_Enable> 
< Skill_1> JavaScript< / Skill_1> 
< Skill_2> Python< / Skill_2> 
< / Skills_Enable> 
 
< /雇主> 
 
 
< / List_Of_Employe>

希望你能帮助我

Mayeul

解决方案

您的样式表需要一些改进，但您距离解决方案并不遥远。这不是一个漂亮的解决方案，但它成功地转换了您的输入XML。 （一个更好的解决方案可能会使用多个模板，而不是每个 for 语句的几个模板）。



清除一些东西



您说：


从我的研究中，我了解到只有IE获得了xml解析器，而对于其他浏览器，我需要一个servor脚本


否， 这不是真的。每个主流浏览器都有一个体面的XML解析器。您不需要任何服务器端代码来解析XML。同样，每个主要的浏览器（IE，Chrome，Firefox，Safari）都附带XSLT处理器，不过只支持XSLT 1.0。 b
$ b


甚至当我使用IE浏览器（11）时，我只有文本没有任何风格，我已经把。


输入XML中的文本内容作为转换的结果通常意味着：您的模板都不能匹配输入元素。您的代码没有被应用，并且采取默认操作：调用内置模板，仅输出所有文本节点。



目前还不清楚为什么没有模板应该适用于您的案例，请告诉我下面的样式表是否会改变输出。


我对你的样式表做了以下修改：


  • 有一个流浪< ; td /> 应该是< / td> ，因为它结束了 td 元素。

  • 为所有属性值添加引号。因为XSLT代码本身必须是格式良好的XML，所以属性值绝对需要用引号（...）。



一个HTML解析器可以处理很多错误（例如未加引号的属性值），但是XML解析器对此非常严格。

 <？xml version =1.0encoding =UTF-8？> 
< xsl：stylesheet version =1.0
 xmlns：xsl =http://www.w3.org/1999/XSL/Transform> 
 
< xsl：template match =/> 
< html> 
< body> 
 
< h2>工人清单< / h2> 
< table border =1> 
< tr bgcolor =＃9acd32> 
 < th colspan =5>基本信息< / th> 
 < th colspan =2>技能启用< / th> 
< / tr> 
< tr> 
< td rowspan =2>名称< / td> 
< td colspan =3>地址< / td> 
< td rowspan =2>电话号码< / td> 
< td rowspan =2>技巧1< / td> 
< td rowspan =2>技巧2< / td> 
< / tr> 
< tr> 
< td>号码< / td> 
< td>街< / td> 
< td>城镇< / td> 
< / tr> 
< xsl：for-each select =List_Of_Employe / Employe> 
< xsl：sort select =Name/> 
< tr> 
< td>< xsl：value-of select =ID/>< / td> 
< td>< xsl：value-of select =Basic_Information / Name/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Number/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Street/>< / td> 
< td>< xsl：value-of select =Basic_Information / Address / Town/>< / td> 
< td>< xsl：value-of select =Basic_Information / Phone_Number/>< / td> 
< td>< xsl：value-of select =Photo/>< / td> 
< td>< xsl：value-of select =Skills_Enable / Skill_1/>< / td> 
< td>< xsl：value-of select =Skills_Enable / Skill_2/>< / td> 
< / tr> 
< / xsl：for-each> 
< / table> 
< / body> 
< / html> 
< / xsl：template> 
 
< / xsl：stylesheet>

另请考虑将以下行添加到样式表中：

 < xsl：output method =htmlindent =yes/>

明确表示您希望输出HTML。



XHTML输出 

 < html> 
< body> 
< h2>工人清单< / h2> 
< table border =1> 
< tr bgcolor =＃9acd32> 
 < th colspan =5>基本信息< / th> 
 < th colspan =2>技能启用< / th> 
< / tr> 
< tr> 
< td rowspan =2>名称< / td> 
< td colspan =3>地址< / td> 
< td rowspan =2>电话号码< / td> 
< td rowspan =2>技巧1< / td> 
< td rowspan =2>技巧2< / td> 
< / tr> 
< tr> 
< td>号码< / td> 
< td>街< / td> 
< td>城镇< / td> 
< / tr> 
< tr> 
< td> 1235< / td> 
< td>詹姆斯邦德< / td> 
< td> 05< / td> 
< td>皇后街< / td> 
< td>伦敦< / td> 
< td> 07876543210< / td> 
< td> James.png< / td> 
< td> XML< / td> 
< td> C＃< / td> 
< / tr> 
< tr> 
< td> 1236< / td> 
< td>福尔摩斯< / td> 
< td> 100< / td> 
< td>王子街< / td> 
< td>伦敦< / td> 
< td> 07765432100< / td> 
< td> Sherlock.png< / td> 
< td> JavaScript< / td> 
< td> Python< / td> 
< / tr> 
< / table> 
< / body> 
< / html>

渲染输出

我没有IE来试用它，但Firefox会将HTML输出呈现为：



最后，让我是短暂的挑剔，它确实应该读员工，而不是雇主。


I have 2 files, file.xml and file.xsl that I have made. I am looking for how to see the result in a browser. From my research I have understood that only IE got an xml parser and that for the others browser I need a servor script. I have also put these lines at the top of my xml file :

 <?xml version="1.0" encoding="UTF-8"?>
 <?xml-stylesheet type="text/xsl" href="Employe.xsl"?>

and these lignes at the top of my xsl file :

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

However, even when i'm using IE (11) I only have the text without any style that I have put. I wanted to display the elemnts in a table but there isn't any.

I am giving you my code for the table if there is any mistakes I haven't found, but normaly it is ok.

Here is the xsl code :

<xsl:template match="/">
<html>
<body>

    <h2>List of Workers</h2>
    <table border="1">
        <tr bgcolor="#9acd32">
            <th rowspan=3> ID </th>
            <th colspan=5> Basic Information </th>
            <th rowspan=3> Picture </th>
            <th colspan=2> Skills enable </th>
        </tr>
        <tr>
            <td rowspan=2> Name </td>
            <td colspan=3> Address </td>
            <td rowspan=2> Phone Number </td>
            <td rowspan=2> Skill 1 </td>
            <td rowspan=2> Skill 2 </td>
        </tr>
        <tr>
            <td> Number </td>
            <td> Street </td>
            <td> Town </td>
        </tr>
        <xsl:for-each select="List_Of_Employe/Employe">
        <xsl:sort select="Name"/>
        <tr>
            <td><xsl:value-of select="ID"/></td>
            <td><xsl:value-of select="Basic_Information/Name"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Number"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Street"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Town"/></td>
            <td><xsl:value-of select="Basic_Information/Phone_Number"/><td/>
            <td><xsl:value-of select="Photo"/></td>
            <td><xsl:value-of select="Skills_Enable/Skill_1"/></td>
            <td><xsl:value-of select="Skills_Enable/Skill_2"/></td>
        </tr>
        </xsl:for-each>
    </table>
</body>
</html>
</xsl:template>

</xsl:stylesheet>

and here is my xml code : 

<List_Of_Employe>



    <Employe>

        <ID> 1235 </ID>

        <Basic_Information>

            <Name> James Bond</Name>

            <Address>
                <Number > 05 </Number>
                <Street> Queen's street </Street>
                <Town> London </Town>
            </Address>

            <Phone_Number> 07876543210 </Phone_Number>

        </Basic_Information>

        <Photo> James.png </Photo>

        <Skills_Enable>
            <Skill_1> XML </Skill_1>
            <Skill_2> C# </Skill_2>
        </Skills_Enable>

    </Employe>

    <Employe>

        <ID> 1236 </ID>

        <Basic_Information>

            <Name> Sherlock Holmes </Name>

            <Address>
                <Number > 100 </Number>
                <Street> Prince's street </Street>
                <Town> London </Town>
            </Address>

            <Phone_Number> 07765432100 </Phone_Number>

        </Basic_Information>

        <Photo> Sherlock.png </Photo>

        <Skills_Enable>
            <Skill_1> JavaScript </Skill_1>
            <Skill_2> Python </Skill_2>
        </Skills_Enable>

    </Employe>


 </List_Of_Employe>

Hoping you will be able to help me

Mayeul

解决方案

Your stylesheet needs some improvement, but you're not far off a solution. It's not a beautiful solution, but it successfully transforms your input XML. (A better solution would have used several templates, not a huge one with several for-each statements).

Clearing up a few things

You say:

From my research I have understood that only IE got an xml parser and that for the others browser I need a servor script

No, that's not true. Every major browser has a decent XML parser. You do not need any server-side code to parse XML. Likewise, every major browser (IE, Chrome, Firefox, Safari) ships with an XSLT processor, though only supporting XSLT 1.0.

However, even when i'm using IE (11) I only have the text without any style that I have put.

Getting nothing but all textual content from the input XML as the result of a transformation usually means: none of your templates could match the input elements. None of your code was applied, and the default action is taken: invoking the built-in templates, that only output all text nodes.

It's unclear to me why no templates should apply in your case, let me know whether the stylesheet I suggest below changes the output.

Stylesheet

I have made the following changes to your stylesheet:

  • There was a stray <td/> that should be </td>, because it ends a td element.
  • Added quotes to all attribute values. Attribute values absolutely need to be in quotes ("..."), since the XSLT code must itself be well-formed XML.

An HTML parser can deal with a lot of errors (e.g. unquoted attribute values), but XML parsers are very strict on this.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<html>
<body>

    <h2>List of Workers</h2>
    <table border="1">
        <tr bgcolor="#9acd32">
            <th rowspan="3"> ID </th>
            <th colspan="5"> Basic Information </th>
            <th rowspan="3"> Picture </th>
            <th colspan="2"> Skills enable </th>
        </tr>
        <tr>
            <td rowspan="2"> Name </td>
            <td colspan="3"> Address </td>
            <td rowspan="2"> Phone Number </td>
            <td rowspan="2"> Skill 1 </td>
            <td rowspan="2"> Skill 2 </td>
        </tr>
        <tr>
            <td> Number </td>
            <td> Street </td>
            <td> Town </td>
        </tr>
        <xsl:for-each select="List_Of_Employe/Employe">
        <xsl:sort select="Name"/>
        <tr>
            <td><xsl:value-of select="ID"/></td>
            <td><xsl:value-of select="Basic_Information/Name"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Number"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Street"/></td>
            <td><xsl:value-of select="Basic_Information/Address/Town"/></td>
            <td><xsl:value-of select="Basic_Information/Phone_Number"/></td>
            <td><xsl:value-of select="Photo"/></td>
            <td><xsl:value-of select="Skills_Enable/Skill_1"/></td>
            <td><xsl:value-of select="Skills_Enable/Skill_2"/></td>
        </tr>
        </xsl:for-each>
    </table>
</body>
</html>
</xsl:template>

</xsl:stylesheet>

Also consider adding the following line to your stylesheet:

<xsl:output method="html" indent="yes"/>

To make it explicit that you'd like to output HTML.

XHTML Output

<html>
   <body>
      <h2>List of Workers</h2>
      <table border="1">
         <tr bgcolor="#9acd32">
            <th rowspan="3"> ID </th>
            <th colspan="5"> Basic Information </th>
            <th rowspan="3"> Picture </th>
            <th colspan="2"> Skills enable </th>
         </tr>
         <tr>
            <td rowspan="2"> Name </td>
            <td colspan="3"> Address </td>
            <td rowspan="2"> Phone Number </td>
            <td rowspan="2"> Skill 1 </td>
            <td rowspan="2"> Skill 2 </td>
         </tr>
         <tr>
            <td> Number </td>
            <td> Street </td>
            <td> Town </td>
         </tr>
         <tr>
            <td> 1235 </td>
            <td> James Bond</td>
            <td> 05 </td>
            <td> Queen's street </td>
            <td> London </td>
            <td> 07876543210 </td>
            <td> James.png </td>
            <td> XML </td>
            <td> C# </td>
         </tr>
         <tr>
            <td> 1236 </td>
            <td> Sherlock Holmes </td>
            <td> 100 </td>
            <td> Prince's street </td>
            <td> London </td>
            <td> 07765432100 </td>
            <td> Sherlock.png </td>
            <td> JavaScript </td>
            <td> Python </td>
         </tr>
      </table>
   </body>
</html>

Rendered Output

I do not have IE to try it out there, but Firefox renders the HTML output to:

Finally, let me be nit-picking for a brief moment, it really should read "Employee", not "Employe".

这篇关于在浏览器中显示xml和xslt的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！

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