如何根据条件创建HTML按钮？ [英] How to create HTML button based on condition?

问题描述

使用以下代码：

 <？PHP 
 if（$ _Session ['WorkMode']] =='New'|| $ _Session ['WorkMode'] ==）
 echo< input id ='Submit'name ='Submit'value ='Submit'type ='button'> ; 
 else 
 echo< input id ='Update'name ='Update'value ='Update'type ='button'>; 
？> 
  

这是渲染按钮的正确方法吗？

解决方案

这是完全有效且可读的。

如果代码行数对您很重要，您也可以这样做：

 <？php $ action =（$ _Session ['WorkMode'] =='New'|| $ _Session ['WorkMode']）？ 提交：更新％> 
< input id =<？php echo $ action？> name =<？php echo $ action？> value =<？php echo $ action？> type =button/> 
  

我的PHP有点生疏，所以我可能会忽略语法，但您明白了。

如果您使用cakephp或symphony等框架，则可以使用助手更轻松地生成按钮。

I am using following code:

<?PHP
      if ($_Session['WorkMode'] == 'New' || $_Session['WorkMode'] == "") 
    echo "<input id='Submit' name='Submit' value='Submit' type='button'>";
      else
    echo "<input id='Update' name='Update' value='Update' type='button'>";
?>

Is this the correct way to render buttons?

解决方案

This is totally valid and readable.

If the number of lines of code is important to you, you could also do:

<?php $action = ($_Session['WorkMode'] == 'New' || $_Session['WorkMode'])? "Submit" : "Update" %>
<input id="<?php echo $action ?>" name="<?php echo $action ?>" value="<?php echo $action ?>" type="button" />

My PHP is a bit rusty so I might be off on the syntax, but you get the idea.

If you use a framework such as cakephp or symphony you can use their helpers to generate buttons more easily.

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