无法将值形式的servlet转发给html [英] Unable to forward the values form servlet to html
本文介绍了无法将值形式的servlet转发给html的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
我试图将userName作为请求发送到html页面作为set属性，但是它并没有在FormDemo中显示消息，请让我知道我要去哪里。
<！DOCTYPE html PUBLIC - // W3C // DTD HTML 4.01 Transitional // EN
http://www.w3.org/TR/html4/loose.dtd\">
< html>
< head>
< meta http-equiv =Content-Typecontent =text / html; charset = UTF-8>
< title>登入表单< / title>
< / head>
< body>
< div align =center>
< form name =loginFormmethod =postaction =loginServlet>
用户名：< input type =textname =username/> <峰; br />
密码：< input type =passwordname =password/> <峰; br />
< input type =submitvalue =Login/>
< / form>
< / div>
< / body>
< / html>
登录servlet.java
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LoginServlet extends HttpServlet {
$ b / **
*
* /
private static final long serialVersionUID = 1L;
$ b保护void doPost（HttpServletRequest请求，
HttpServletResponse响应）抛出ServletException，IOException {
//读取表单字段
字符串username = request.getParameter （用户名）;
String password = request.getParameter（password）;
System.out.println（username：+ username）;
System.out.println（password：+ password）;
request.setAttribute（userName，username）;
request.getRequestDispatcher（/ FormDemo.html）。forward（request，response）;
}
}
FormDemo.html
<！DOCTYPE html PUBLIC - // W3C // DTD HTML 4.01 Transitional // EN
http：// www.w3.org/TR/html4/loose.dtd\">
< html>
< head>
< meta http-equiv =Content-Typecontent =text / html; charset = UTF-8>
< title>表单演示< / title>
< / head>
< body>
< p> <％= request.getAttribute（userName）％>< / p>
< / body>
< / html>
Web.xml
<？xml version =1.0encoding =UTF-8？>
< web-app xmlns：xsi =http://www.w3.org/2001/XMLSchema-instancexmlns =http://java.sun.com/xml/ns/javaeexsi ：schemaLocation =http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsdid =WebApp_IDversion =3.0 >
< display-name> LexisNexis< / display-name>
< welcome-file-list>
< welcome-file> index.html< / welcome-file>
< / welcome-file-list>
< servlet>
< servlet-name> LoginServlet< / servlet-name>
< servlet-class> package.LoginServlet< / servlet-class>
0< / load-on-startup>
< / servlet>
< servlet-mapping>
< servlet-name> LoginServlet< / servlet-name>
< url-pattern> / loginServlet< / url-pattern>
< / servlet-mapping>
< servlet>
< servlet-name> DemoServlet< / servlet-name>
< servlet-class> package.DemoServlet< / servlet-class>
< / servlet>
< servlet-mapping>
< servlet-name> DemoServlet< / servlet-name>
< url-pattern> / demoServlet< / url-pattern>
< / servlet-mapping>
< / web-app>
解决方案
没有办法将这样的值写入一个普通的HTML页面。您需要使用 JSP 来执行此操作。
I am trying to Send userName as request to html page as set attribute, But it is not displaying the msgs in FormDemo, Please let me know where i am going wrong.
Login page
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Login Form</title>
</head>
<body>
<div align="center">
<form name="loginForm" method="post" action="loginServlet">
Username: <input type="text" name="username"/> <br/>
Password: <input type="password" name="password"/> <br/>
<input type="submit" value="Login" />
</form>
</div>
</body>
</html>
Login servlet.java
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LoginServlet extends HttpServlet {
/**
*
*/
private static final long serialVersionUID = 1L;
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
// read form fields
String username = request.getParameter("username");
String password = request.getParameter("password");
System.out.println("username: " + username);
System.out.println("password: " + password);
request.setAttribute("userName", username);
request.getRequestDispatcher("/FormDemo.html").forward(request,response);
}
}
FormDemo.html
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Form Demo</title>
</head>
<body>
<p> <%= request.getAttribute("userName") %></p>
</body>
</html>
Web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>LexisNexis</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>LoginServlet</servlet-name>
<servlet-class>package.LoginServlet</servlet-class>
<load-on-startup>0</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>LoginServlet</servlet-name>
<url-pattern>/loginServlet</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>DemoServlet</servlet-name>
<servlet-class>package.DemoServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>DemoServlet</servlet-name>
<url-pattern>/demoServlet</url-pattern>
</servlet-mapping>
</web-app>
解决方案
There is not a way to write values like this into a plain HTML page. You will need to use a JSP to do this.
这篇关于无法将值形式的servlet转发给html的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
查看全文
