Javascript使用RegExp替换字符串模式？ [英] Javascript replacing string pattern using RegExp?

问题描述

我想删除用方括号括起来的数字字符串模式的任何发生，例如[1]，[25]，[46]，[345]（我认为括号内最多3个字符应该没问题）。我想用空字符串替换它们，，即删除它们。

我知道这可以用正则表达式来完成，但我对此很新颖。这是我所拥有的不做任何事情：

  var test =这是一个带有参考文献的测试句子[12] ; 
 removeCrap（test）; 
 alert（test）; 
 
函数removeCrap（string）{
 
 var pattern = new RegExp（[...]）; 
 string.replace（pattern，）; 
  

}

任何人都可以帮我解决有了这个？希望问题清楚。谢谢。

解决方案

1. [] 在正则表达式中有特殊含义，它会创建一个 字符类 。如果你想直接匹配这些字符，你必须将它们转义。

replace ^[docs] 只会替换第一个出现的字符串/表达式，除非您设置了全局标志/修饰符。 c>替换 返回新字符串，但不会就地更改字符串。

考虑到这一点，应该这样做：

  var test =这是一个参考文献[12]测试句子; 
 test = test.replace（/ \ [\ d + \] / g，''）; 
 alert（test）; 
  

正则表达式解释：

， /.../ 是一个正则表达式文字。 g 是全局标志。

• \ [/ code> [code> [字面意思]


• \ d + 匹配一个或多个数字


• \] 匹配] / li>
  

要了解有关正则表达式的更多信息，请查看 MDN文档和 http：// www .regular-expressions.info / 。

I want to remove any occurances of the string pattern of a number enclosed by square brackets, e.g. [1], [25], [46], [345] (I think up to 3 characters within the brackets should be fine). I want to replace them with an empty string, "", i.e. remove them.

I know this can be done with regular expressions but I'm quite new to this. Here's what I have which doesn't do anything:

var test = "this is a test sentence with a reference[12]";
removeCrap(test);
alert(test);

function removeCrap(string) {

var pattern = new RegExp("[...]"); 
string.replace(pattern, "");

}

Could anyone help me out with this? Hope the question is clear. Thanks.

解决方案

1. [] has a special meaning in regular expressions, it creates a character class. If you want to match these characters literally, you have to escape them.

2. replace ^[docs] only replaces the first occurrence of a string/expression, unless you set the global flag/modifier.

3. replace returns the new string, it does not change the string in-place.

Having this in mind, this should do it:

var test = "this is a test sentence with a reference[12]";
test = test.replace(/\[\d+\]/g, '');
alert(test);

Regular expression explained:

In JavaScript, /.../ is a regex literal. The g is the global flag.

• \[ matches [ literally
• \d+ matches one or more digits
• \] matches ] literally

To learn more about regular expression, have a look at the MDN documentation and at http://www.regular-expressions.info/.

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