在HTML5中，我可以同时播放多次相同的声音吗？ [英] In HTML5, can I play the same sound more than once at the same time?

问题描述

我正在制作一个游戏，其中经常播放声音。我注意到声音在播放时不会再播放。例如，玩家与墙壁碰撞，发出砰砰声。但是，如果玩家与一面墙碰撞，然后迅速与另一面墙发生碰撞，则只会发出一声砰砰的声音，我相信这是因为第一声音没有完成。真的吗？我应该如何避免这种情况？我想过将声音预加载三次，总是播放不同的声音副本，但这看起来相当愚蠢...

I'm making a game, in which sounds are often played. I noticed that a sound wont play again while it is being played. For example, the player collides with a wall, a "thump" sound is played. But, if the player collides with one wall, and then quickly collides with another wall, only one "thump" sound is played, and I believe that this happens because the first sound didn't finish. Is that true? How should I avoid this? I thought of preloading the sound three times, always playing a different copy of that sound, but this seems rather stupid...

已解决：

原来我是对的...你需要预先加载多个版本的声音，然后循环播放它们。

Turns out I was right... You need to preload multiple versions of the sound and then circularly play them.

代码：

var ns = 3; //The number of sounds to preload. This depends on how often the sounds need to be played, but if too big it will probably cause lond loading times.
var sounds = []; //This will be a matrix of all the sounds

for (i = 0; i < ns; i ++) //We need to have ns different copies of each sound, hence:
    sounds.push([]);

for (i = 0; i < soundSources.length; i ++)
    for (j = 0; j < ns; j ++)
        sounds[j].push(new Audio(sources[i])); //Assuming that you hold your sound sauces in a "sources" array, for example ["bla.wav", "smile.dog" "scream.wav"] 

var playing = []; //This will be our play index, so we know which version has been played the last.

for (i = 0; i < soundSources.length; i ++)
    playing[i] = 0; 

playSound = function(id, vol) //id in the sounds[i] array., vol is a real number in the [0, 1] interval
{
    if (vol <= 1 && vol >= 0)
        sounds[playing[id]][id].volume = vol;
    else
        sounds[playing[id]][id].volume = 1;

    sounds[playing[id]][id].play();
    ++ playing[id]; //Each time a sound is played, increment this so the next time that sound needs to be played, we play a different version of it,

    if (playing[id] >= ns)
        playing[id] = 0;
}

推荐答案

多次加载声音模拟复音。以循环方式播放它们。在 matthewtoledo.com 查看我的演示。具体来说，函数_initSoundBank（）

Load the sound several times to simulate polyphony. Play them in round-robin fashion. Check out my demo at matthewtoledo.com. Specifically, the function _initSoundBank()

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