使用preg_match识别强密码 [英] Using preg_match to identify a strong password

问题描述

我曾想过使用preg_match（）来检查是否正确输入了密码。我想要至少1个大写字母，至少1个小写字母，至少一个数字，以及至少一个特殊字符。这是我正在使用的：

I had thought to use preg_match() to check if a password is correctly entered. I want at least 1 uppercase letter, at least 1 lowercase letter, at least one number, and at least one special char. Here's what I am using:

$pattern = "(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$";

此正则表达式在HTML的模式字段中正常工作。但我需要确保它也经过旧版浏览器的验证。

This regex is working fine in HTML's "pattern" field. But I need to ensure that it's also verified for older browsers.

我的PHP代码是这样的：

My PHP code is this:

if (!(preg_match($pattern, $loginpassword))) {echo "Password must include one uppercase letter, one lowercase letter, one number, and one special character such as $ or %."; die;}

我认为它工作得很好，除非我使用密码1 @ abcdeF它也失败了匹配。 PHP代码似乎工作，但没有密码匹配，即使它应该适合模式。 HTML5将让它通过，所以我怀疑正则表达式语句是正确的，但有关我在PHP中的设置是有缺陷的。任何人都可以看到我缺少的东西吗？

I thought it was working great except when I use the password 1@abcdeF it also fails to match. The php code seems to work but no password ever matches, even when it SHOULD fit the pattern. HTML5 will let it through so I suspect the regex statement is correct, but something about my setup in PHP is flawed. Can anyone see what I'm missing?

推荐答案

PHP正则表达式也需要正则表达式分隔符，所以使用：

PHP regex needs regex delimiters also, so use:

$pattern = '/(?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$/';

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