将DOCTYPE添加到Scala XML的最简单方法？ [英] Simplest way to add DOCTYPE to Scala XML?
问题描述
如何在Scala XML中创建这个miminal HTML5：
<！DOCTYPE html>< title>< / title>< p>< / p>< / html> ？
How can I make this miminal HTML5 in Scala XML:
<!DOCTYPE html><title></title><p></p></html>?
当然，在Scala中制作类似HTML的XML非常简单：
Of course it's simple to make an HTML-like XML in Scala:
> val html = <html><title></title><p></p></html>
html: scala.xml.Elem = <html><title></title><p></p></html>
但是，如何注入 DOCTYPE 属性前缀 html 标签？
However, how can I inject a DOCTYPE attribute prefixed in the html tag?
我试过的两条路线：
使用 scala.xml.Document 和 scala.xml.DocType ，但两者似乎都基于写出文件或流，而我只是将这个XML对象保存在内存中。看起来像太多仪式。
Two routes I tried:
Using the scala.xml.Document and scala.xml.DocType, but both seemed predicated on writing out a file or stream, whereas I'm just keeping this XML object in memory. Seemed like too much ceremony.
使用 1601677>属性，
> import scala.xml.{Null, Text, Attribute}
> val d = <html /> % Attribute(None, "!DOCTYPE", Text(""), Null)
d: scala.xml.Elem = <html !DOCTYPE=""></html>
这是关闭的，但不是带前缀的属性和顽皮的作业。
which is close, but not a prefixed attribute and with a naughty assignment.
推荐答案
您可以使用XML的write方法来获取java.io.Writer而不是File。使用java.io.StringWriter是直截了当的：
You can use XML's write method that takes a java.io.Writer instead of a File. Using java.io.StringWriter is straight forward:
val w = new java.io.StringWriter()
val html = <html><body><p>Que pasa?!</p></body></html>
xml.XML.write(w, html, "UTF-8", xmlDecl = false, doctype =
xml.dtd.DocType("html", xml.dtd.SystemID("about:legacy-compat"), Nil))
w.toString
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