如何通过前缀获取所有data- *属性 [英] How to get all data-* attributes by Prefix
问题描述
我有这样的标签:
< a href =#id =ssddata-toggle =popoverdata-info1 =demo text:1data-info2 =demo text:2data-info3 =demo text3> Link< / a>
当我点击此链接时,我有这样的功能
$('#ssd')。click(function(event){
var customData;
//获取所有自定义数据的代码格式如data-info *
});
注意,data-info * like属性可以是任意数字,这意味着你可以看到1个其中,名为data-info1,或名称为data-info1,data-info2,data-info3。
我怎么做,我抬起头来JQuery选择器,类似于属性开始选择器[名称^ =值]将不起作用,因为这里的变化是在名称...
如果我 console.log($('#ssd')。data());
我将获得一个具有我不需要的额外属性的对象,切换:popover,bs.popover:Popover
有任何建议吗?
这就是我做的:
dataFullList = $(this).data();
$ .each(dataFullList,function(index,value){
if(index!==toggle&& index!==bs.popover){
item .name = value.split(:)[0];
item.number = value.split(:)[1];
dataIWant.push(item);
}
});
所以我将获得一个 dataIWant
数组我不需要的东西。
定位数据的所有元素 - *
以
开头自定义jQuery选择器选择器:dataStartsWith()
这是一个自定义jQuery选择器,可以帮助你:
给出 数据 -
foo-bar
前缀,目标以下元素:
data-foo-bar
data-foo-bar-baz
但不:
data-foo-someting
data-something
jQuery.extend(jQuery.expr [' :'],{dataStartsWith:function(el,i,p,n){var pCamel = p [3] .replace(/ - ([az])/ ig,function(m,$ 1){return $ 1。 toUpperCase(); }); return Object.keys(el.dataset).some(function(i,v){return i.indexOf(pCamel)> -1;}); }}); //使用:$('p:dataStartsWith(foo-bar)')。css({color:red}); //获取数据属性列表:$('p:dataStartsWith(foo-bar)')。each(function(i,el){console.log(el.dataset);});
< script src =https://ajax.googleapis.com/ajax /libs/jquery/2.1.1/jquery.min.js\"></script><p data-foo-bar =a>我有data-foo-bar< / p>< p data-foo-bar-baz =bdata-extra =bbb>我有data-foo-bar-baz< / p>< p data-bar =a>我有数据栏请勿选择我< / p>< p data-something =b>我有数据 - 请勿选择我< / p>
自定义jQuery方法 $()。dataStartsWith()
$。fn.dataStartsWith = function(p){var pCamel = p.replace(/ - ([az])/ ig ,function(m,$ 1){return $ 1.toUpperCase();}); return this.filter(function(i,el){return Object.keys(el.dataset).some(function(v){return v.indexOf(pCamel)> -1;});});}; $ ( 'p')dataStartsWith( 富杆)的CSS({色 红})。。
< script src =https:// ajax。 googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js\"></script><p data-foo-bar =a>我有data-foo-bar< / p>< p data-foo-bar-baz =bdata-extra =bbb>我有data-foo-bar-baz< / p>< p data-bar =a>我有数据栏请勿选择我< / p>< p data-something =b>我有数据 - 请勿选择我< / p>
I have a tag like this:
<a href="#" id="ssd" data-toggle="popover" data-info1="demo text: 1" data-info2="demo text: 2" data-info3="demo text3">Link</a>
When I click this link, I have a function like this
$('#ssd').click(function (event) {
var customData;
// Code to get all the custom data in format like data-info*
});
Note, the data-info* like attributes could be any number, that means you could see 1 one of them, named data-info1, or there of them, named data-info1, data-info2, data-info3.
How would I do that, I looked up the JQuery selectors, something like Attribute Starts With Selector [name^="value"] won't work because the variation here is on name...
If I console.log($('#ssd').data());
I will get an object with extra attributes that I don't need, toggle: "popover", bs.popover: Popover
Any suggestions?
This is what I did:
dataFullList = $(this).data();
$.each(dataFullList, function (index, value) {
if (index !== "toggle" && index !== "bs.popover") {
item.name = value.split(":")[0];
item.number = value.split(":")[1];
dataIWant.push(item);
}
});
So I will get a dataIWant
array without stuff I don't need.
Target all elements which data-*
starts with
Custom jQuery selector selector:dataStartsWith()
Here's a custom jQuery selector that will help you to:
Given the data-
foo-bar
prefix , target the following elements:
data-foo-bar
data-foo-bar-baz
but not:
data-foo-someting
data-something
jQuery.extend(jQuery.expr[':'], {
"dataStartsWith" : function(el, i, p, n) {
var pCamel = p[3].replace(/-([a-z])/ig, function(m,$1) { return $1.toUpperCase(); });
return Object.keys(el.dataset).some(function(i, v){
return i.indexOf(pCamel) > -1;
});
}
});
// Use like:
$('p:dataStartsWith(foo-bar)').css({color:"red"});
// To get a list of data attributes:
$('p:dataStartsWith(foo-bar)').each(function(i, el){
console.log( el.dataset );
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p data-foo-bar="a">I have data-foo-bar</p>
<p data-foo-bar-baz="b" data-extra="bbb">I have data-foo-bar-baz</p>
<p data-bar="a">I have data-bar DON'T SELECT ME</p>
<p data-something="b">I have data-something DON'T SELECT ME</p>
Custom jQuery Method $().dataStartsWith()
$.fn.dataStartsWith = function(p) {
var pCamel = p.replace(/-([a-z])/ig, function(m,$1) { return $1.toUpperCase(); });
return this.filter(function(i, el){
return Object.keys(el.dataset).some(function(v){
return v.indexOf(pCamel) > -1;
});
});
};
$('p').dataStartsWith("foo-bar").css({color:"red"});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p data-foo-bar="a">I have data-foo-bar</p>
<p data-foo-bar-baz="b" data-extra="bbb">I have data-foo-bar-baz</p>
<p data-bar="a">I have data-bar DON'T SELECT ME</p>
<p data-something="b">I have data-something DON'T SELECT ME</p>
这篇关于如何通过前缀获取所有data- *属性的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!