如何获取HTTP 404响应的响应内容 [英] How to get the response content of an HTTP 404 response

问题描述

获取HTTP 404响应的内容是否比通过tcp直接访问主机更简单？

Is there an easier way of getting the content of an HTTP 404 response than directly accessing the host via tcp?

这是包含内容的404响应的示例：

This is a sample of a 404 response with content:

HTTP/1.1 404 Object Not Found
Server: CouchDB/1.3.0 (Erlang OTP/R15B03)
Date: Wed, 24 Jul 2013 08:32:50 GMT
Content-Type: text/plain; charset=utf-8
Content-Length: 41
Cache-Control: must-revalidate

{"error":"not_found","reason":"missing"}

推荐答案

Rebol HTTP方案真的不是用这个设计的记住，它的目的是按照你在浏览器中的方式阅读内容，而不是通过HTTP服务。

The Rebol HTTP scheme really isn't designed with this in mind, it's geared toward reading content the way you would in a browser, not services over HTTP.

在说这个，你可以破解协议来颠覆Rebol 2的方式处理不同的响应代码：

In saying that, you can hack the protocol to subvert how Rebol 2 handles different response codes:

in-http-scheme: func [does [block!]][
    do bind :does bind? last body-of get in system/schemes/http/handler 'open
]

in-http-scheme [
    remove-each [code response] response-actions [find [400 403 404] code]
    append response-actions [400 success 403 success 404 success]
]

这里需要注意的是HTTP协议必须已经启动（任何http端口打开/读取）。 response-actions ：

select body-of get in system/schemes/http/handler 'open quote response-actions:

您可以获取最后一个响应行因此：

You can get the last response line thus:

in-http-scheme [response-line]

或者你需要一个专为HTTP服务设计的方案。我有一个 REST协议（两个版本，一个使用cURL ，并使用定制的HTTP方案有效，但效果不佳。虽然适用于Rebol 2.我计划使用Rebol 3版本。

Alternatively you are going to need a scheme designed for services over HTTP. I have a REST protocol (two versions, one that uses cURL, and one that uses a customised HTTP scheme that works, but isn't as good). Though are for Rebol 2. I have plans for a Rebol 3 version.

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