如何使用python urllib在HTTP / 1.1中保持活力 [英] How to stay alive in HTTP/1.1 using python urllib

问题描述

现在我这样做：（Python3，urllib）

For now I am doing this: (Python3, urllib)

url = 'someurl'
headers = '(('HOST', 'somehost'), /  
            ('Connection', 'keep-alive'),/
            ('Accept-Encoding' , 'gzip,deflate'))
opener = urllib.request.build_opener(urllib.request.HTTPCookieProcessor())
for h in headers:
    opener.addheaders.append(x)
data = 'some logging data' #username, pw etc.
opener.open('somesite/login.php, data)

res = opener.open(someurl)
data = res.read()
... some stuff here...
res1 = opener.open(someurl2)
data = res1.read()
etc.

这是怎么回事;

我一直从服务器获取gzipped响应我保持登录状态（我正在获取一些内容，如果我没有登录则无法使用）但我认为每个请求openner.open之间的连接都在下降;

I keep getting gzipped responses from server and I stayed logged in (I am fetching some content which is not available if I were not logged in) but I think the connection is dropping between every request opener.open;

我认为因为连接非常慢而且似乎每次都有新的连接。两个问题：

I think that because connecting is very slow and it seems like there is new connection every time. Two questions:

a）我如何测试实际连接是否保持活着/死亡？
b）如何让它保持活力在请求其他网址之间？

a)How do I test if in fact the connection is staying-alive/dying
b)How to make it stay-alive between request for other urls ?

小心：）

推荐答案

这将是一个非常延迟的答案，但是：

This will be a very delayed answer, but:

您应该看到 urllib3 。它适用于Python 2.x但是当你看到他们的README文档时你会明白这个想法。

You should see urllib3. It is for Python 2.x but you'll get the idea when you see their README document.

是的，urllib默认不保持连接活着，我现在我正在为Python 3实现urllib3以保留在我的工具包中：）

And yes, urllib by default doesn't keep connections alive, I'm now implementing urllib3 for Python 3 to be staying in my toolbag :)

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