从CGI C模块返回http错误代码 [英] return http error code from CGI C module

问题描述

我有一个用C& C编写的CGI模块。对于某些情况，我想从此模块返回HTTP错误400。问题是 - 我不知道如何从模块返回HTTP错误。

I've a CGI module written in C & for some condition I want to return HTTP error 400 from this module. The problem is - I don't know how to return HTTP error from the module.

在我的模块中看起来像'return（-1）'，返回500内部服务器错误。我已经尝试过返回400等但是静脉。我甚至试过printf（状态：400）;返回-1之前（如下所示：如何从C ++ CGI程序返回500 HTTP状态）但这不起作用。

Looks like the 'return(-1)' in my module, returns the 500 internal server error. I've tried returning 400 etc. but in vein. I've even tried "printf("Status:400");" before returning -1 (as suggested here: How to return a 500 HTTP status from a C++ CGI program ) but that didn't work.

对此有任何建议将不胜感激。

Any advice on this would be appreciated.

编辑：[已解决]我能够从python模块（稍后由此C CGI模块调用）返回HTTP错误代码。所以没有尝试下面评论中提到的建议。感谢您提供帮助。

[solved] I was able to return HTTP error code from the python module (which is called later by this C CGI module). So didn't get to try the suggestion mentioned in comments below. Thanks for offering help, though.

推荐答案

要将HTTP错误400返回给HTTP客户端，您必须编写HTTP状态行to stdout，像这样：

To return HTTP error 400 to the HTTP client, you have to write the HTTP status line to stdout, like this:

printf("Status: 400 Bad Request\n");

参考： https://tools.ietf.org/html/rfc3875

状态标题字段包含3位整数结果代码
表示脚本尝试处理
请求的成功程度。

The Status header field contains a 3-digit integer result code that indicates the level of success of the script's attempt to handle the request.

  Status         = "Status:" status-code SP reason-phrase NL
  status-code    = "200" | "302" | "400" | "501" | extension-code
  extension-code = 3digit
  reason-phrase  = *TEXT

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