URL存在时，urllib2捕获404错误 [英] urllib2 catches 404 error while URL exists

问题描述

我遇到了一个奇怪的错误：urllib2捕获404错误，同时打开一个有效的URL。我在浏览器中尝试了它，可以打开网址。我也传递了用户代理。

I faced with strange bug: urllib2 catches 404 error, while openning a valid url. I tryed it in browser, the url can be opened. Also I pass user-agent.

import urllib.request as urllib2
uri = 'https://i.ytimg.com/vi/8Sii8G5CNvY/hqdefault.jpg?custom=true&w=196&h=110&stc=true&jpg444=true&jpgq=90&sp=68&sigh=OIIIAPOKNtx1OiZbAqdORlzl92g'
try:
  req = urllib2.Request(uri, headers={ 'User-Agent': 'Mozilla/5.0' })
  file = urllib2.urlopen(req)
except urllib2.HTTPError as err:
  if err.code == 404:
    return "Not Found"

为什么我收到此错误？感谢您的回答。

Why I get this error? Thank you for answers.

推荐答案

如果您想要获取正文，只需阅读<$ c $的错误回复c> err.read（）：

If you want to get the body anyway, simply read the error response with an err.read():

import urllib2
uri = 'https://i.ytimg.com/vi/8Sii8G5CNvY/hqdefault.jpg?custom=true&w=196&h=110&stc=true&jpg444=true&jpgq=90&sp=68&sigh=OIIIAPOKNtx1OiZbAqdORlzl92g'
try:
  req = urllib2.Request(uri, headers={ 'User-Agent': 'Mozilla/5.0' })
  file = urllib2.urlopen(req)
except urllib2.HTTPError as err:
  if err.code == 404:
    print "Not Found"
    print err.read()

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