浏览器检测Python / mod_python？ [英] Browser Detection Python / mod_python?

问题描述

我想在数据库中保留一些有关用户和位置的统计信息。例如，我想存储Mozilla，Firefox，Safari，Chrome，IE等...以及版本，可能还有操作系统。

I want to keep some statistics about users and locations in a database. For instance, I would like to store "Mozilla","Firefox","Safari","Chrome","IE", etc... as well as the versions, and possibly the operating system.

我想从Python找到的是这个字符串;

What I am trying to locate from Python is this string;

Mozilla / 5.0（X11; U; Linux i686; en-US; rv：1.9.0.14）Gecko / 2009090216 Ubuntu / 9.04（jaunty）Firefox / 3.0.14

Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.0.14) Gecko/2009090216 Ubuntu/9.04 (jaunty) Firefox/3.0.14

有没有一种有效的方法来使用Python或mod_python来检测http用户代理/浏览器？

Is there an efficient way to use Python or mod_python to detect the http user agent/browser?

推荐答案

HTTP_USER_AGENT 包含此信息，并将在您的应用程序使用的环境变量中传递。在mod_python中，这表示为：

HTTP_USER_AGENT contains this information, and will be passed in the environment variables your application uses. In mod_python, this is expressed as:

def my_request_handler(req):
    req.add_common_vars()
    agent = req.subprocess_env.get("HTTP_USER_AGENT")

    # `agent` now contains the full user agent of the browser, or None

这是一个基本的CGI事情，但这就是mod_python给你的方式。

It's a basic CGI thing, but this is how mod_python gives it to you.

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