在android中通过http post方法发送json对象 [英] Sending json object via http post method in android

问题描述

已提供的NOT DUPLICATE.Link是旧版本。http客户端已在api23中删除

its NOT DUPLICATE.Link that has been provided is an OLD one."http client" has been removed in api23

我想发送json对象：

I want to send json object:

{"emailId":"[e-mail]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

到网址：

http://10digimr.mobimedia.in / api / mobile_retailer / update_profile
我该怎么做？
通过邮寄方式？

http://10digimr.mobimedia.in/api/mobile_retailer/update_profile How do i do it? via post method?

方法：

 POST /api/mobile_retailer/update_profile

强制性密钥：

{"emailId","address"}

请求JSON：

{"emailId":"[e-mail]","address":"Naya bans","city":"Noida","pincode":"201301","account_number":"91123546374208","bank_name":"Axis Bank","branch_name":"91123546374208","ifsc_code":"UTI0000879"}

回复：

{"message":"Mail Send","data":true,"status":200}

推荐答案

定义一个类 AsyncT 并在 onCreate 方法使用：

Define a class AsyncT and call it in onCreate method using:

AsyncT asyncT = new AsyncT();
asyncT.execute();

班级定义：

class AsyncT extends AsyncTask<Void,Void,Void>{

        @Override
        protected Void doInBackground(Void... params) {

            try {
                URL url = new URL(""); //Enter URL here
                HttpURLConnection httpURLConnection = (HttpURLConnection)url.openConnection();
                httpURLConnection.setDoOutput(true);
                httpURLConnection.setRequestMethod("POST"); // here you are telling that it is a POST request, which can be changed into "PUT", "GET", "DELETE" etc.
                httpURLConnection.setRequestProperty("Content-Type", "application/json"); // here you are setting the `Content-Type` for the data you are sending which is `application/json`
                httpURLConnection.connect();

                JSONObject jsonObject = new JSONObject();
                jsonObject.put("para_1", "arg_1");

                DataOutputStream wr = new DataOutputStream(httpURLConnection.getOutputStream());
                wr.writeBytes(jsonObject.toString());
                wr.flush();
                wr.close();

            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }

            return null;
        }


    }

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