在web视图拦截POST请求 [英] Intercept POST requests in a WebView

问题描述

我的深化发展Android应用程序过滤请求（用白名单），并使用自定义的 SSLSocketFactory的。对于这一点，我已经开发了一个自定义的 WebViewClient ，我已经覆盖了 shouldInterceptRequest 方法。我可以过滤，用我的的SocketFactory 的GET请求，但我不能拦截POST请求。

那么，有没有办法拦截在POST请求的WebView ？

下面是shouldInterceptRequest方法的code：

 公众最终WebResourceResponse shouldInterceptRequest（web视图查看，串urlStr）{
    URI URI = URI.create（urlStr）;
    字符串模式= uri.getScheme（）;
    //如果方​​案未HTTP（S），让默认的WebView管理它
    如果（HTTP.equals（路线）及！＆安培;！的https.equals（方案））{
        返回null;
    }
    网址URL = URI.toURL（）根据;

    如果（doCancelRequest（URL））{
        //空响应
        Log.d（TAG，URL过滤：+网址）;
        返回新WebResourceResponse（text / plain的，UTF-8，新EmptyInputStream（））;

    } 其他 {
        Log.d（TAG，网址：+网址）;

        HttpURLConnection的康恩=（HttpURLConnection类）url.openConnection（）;
        conn.setRequestProperty（用户代理，mSettings.getUserAgentString（））;

        //配置连接
        configureConnection（康涅狄格州）;

        字符串MIMETYPE = conn.getContentType（）;
        字符串编码= conn.getContentEncoding（）;

        如果（MIMETYPE = NULL和放大器;！＆安培; mimeType.contains（CONTENT_TYPE_SPLIT））{
            的String []分割= mimeType.split（CONTENT_TYPE_SPLIT）;
            MIMETYPE =分割[0];

            匹配器匹配= CONTENT_TYPE_PATTERN.matcher（分裂[1]）;
            如果（matcher.find（））{
                编码= matcher.group（1）;
            }
        }

        InputStream的是= conn.getInputStream（）;
        返回新WebResourceResponse（MIMETYPE，编码，就是）;
    }
}
 

解决方案

使用GET而不是POST。

已知问题： HTTP：//$c$c.google.com/p /安卓/问题/详细信息？ID = 9122

在这里回答为好： <一href="http://stackoverflow.com/questions/3664440/android-how-to-intercept-a-form-post-in-android-webviewclient-on-api-level-4">Android - 如何拦截安卓WebViewClient表单POST的API级别4

I'm developping an Android application filtering the requests (with a white list) and using a custom SSLSocketFactory. For this, I've developed a custom WebViewClient and I have overridden the shouldInterceptRequest method. I can filter and use my SocketFactory with the GET requests but I can't intercept the POST requests.

So, is there a way to intercept the POST requests in a WebView ?

Here is the code of the shouldInterceptRequest method :

public final WebResourceResponse shouldInterceptRequest(WebView view, String urlStr) {
    URI uri = URI.create(urlStr);
    String scheme = uri.getScheme();
    // If scheme not http(s), let the default webview manage it
    if(!"http".equals(scheme) && !"https".equals(scheme)) {
        return null;
    }
    URL url = uri.toURL();

    if(doCancelRequest(url)) {
        // Empty response
        Log.d(TAG, "URL filtered: " + url);
        return new WebResourceResponse("text/plain", "UTF-8", new EmptyInputStream());

    } else {
        Log.d(TAG, "URL: " + url);

        HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setRequestProperty("User-Agent", mSettings.getUserAgentString());

        // Configure connections
        configureConnection(conn);

        String mimeType = conn.getContentType();
        String encoding = conn.getContentEncoding();

        if(mimeType != null && mimeType.contains(CONTENT_TYPE_SPLIT)) {
            String[] split = mimeType.split(CONTENT_TYPE_SPLIT);
            mimeType = split[0];

            Matcher matcher = CONTENT_TYPE_PATTERN.matcher(split[1]);
            if(matcher.find()) {
                encoding = matcher.group(1);
            }
        }

        InputStream is = conn.getInputStream();
        return new WebResourceResponse(mimeType, encoding, is);
    }
}

解决方案

Use GET instead of POST.

Known issue: http://code.google.com/p/android/issues/detail?id=9122

Was answered here as well: Android - how to intercept a form POST in android WebViewClient on API level 4

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