Java级别计算器if语句返回错误的值(新手) [英] Java level calculator if statement returning the wrong value (Newbie)

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本文介绍了Java级别计算器if语句返回错误的值(新手)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在学习一些Java,并决定做一些简单的事情,但它仍然会返回错误的值...我不知道为什么我确定有一些未经训练的眼睛没有接受的东西

i'm learning some Java and decided to do something simple but it keeps returning the wrong value... i don't know why i'm sure there something that my untrained eye isn't picking up on

如果您有替代我的代码ANSWER我的问题首先然后推荐替代方案,我真的很讨厌那些忘记我们所有人开始的无知傲慢的人......

Please if you have an alternative to my code ANSWER my question first and then recommend the alternative, i really hate ignorant arrogant people who forgot where we all started off...

import java.util.Scanner;
import java.lang.*;

public class HelloWorld{
public static void main(String args[]){
    int userlevel = 0;
    int userxp=12;
    int level1xp=0, level2xp=1, level3xp=10, level4xp=15, level5xp=25;
    int level1=1, level2=2, level3=3, level4=4, level5=5;

    if (userxp <=level1xp){
        userlevel=1;
    }else if (userxp >=level1xp || userxp <level3xp){
        userlevel=level2;
        System.out.println(userlevel);
    }else if (userxp >= level3xp || userxp <level4xp){
        userlevel=level3;
        System.out.println(userlevel);
    }else if (userxp >=level3xp || userxp <level5xp){
        userlevel=level4;
    }else if (userxp == level5xp){
        userlevel=level5;
    }else{
        System.out.println("You are a cheat");
    }

}






控制台返回



2


console returns

2

推荐答案

 if (userxp >=level1xp || userxp <level3xp){

那应该是&& 而不是 ||

我的最小建议是完全放弃第一个条件。

And my minimal suggestion would be to completely drop the first condition.

因为你在else分支,你已经检查过XP不低于上一级要求。

Since you are in the else branch, you have already checked that the XP is not lower than the previous level requirement.

 if (userxp <level2xp){
        userlevel=1;
    }else if ( userxp <level3xp){
        userlevel=level2;
        System.out.println(userlevel);
    }else if ( userxp <level4xp){
        userlevel=level3;
        System.out.println(userlevel);
    }else if (userxp <level5xp){
        userlevel=level4;
    }else if (userxp == level5xp){
        userlevel=level5;
    }else{
        System.out.println("You are a cheat");
    }

这篇关于Java级别计算器if语句返回错误的值(新手)的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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