Python if语句不能按预期工作 [英] Python if statement doesn't work as expected

问题描述

我目前有代码：

fleechance = random.randrange(1,5)
print fleechance
if fleechance == 1 or 2:
    print "You failed to run away!"
elif fleechance == 4 or 3:
    print "You got away safely!"

fleechance一直打印为3或4，但我继续得到结果你没能跑远！ ，谁能告诉我为什么会这样？

fleechance is constantly printing as 3 or 4, but I continue to get the result "You failed to run away!" ,can anyone tell me why this is happening?

推荐答案

表达式 fleechance == 1或2 相当于（fleechance == 1）或（2）。数字 2 始终被视为真实。

The expression fleechance == 1 or 2 is equivalent to (fleechance == 1) or (2). The number 2 is always considered "true".

试试这个：

if fleechance in (1, 2):

编辑：在你的情况下（只有2种可能性），以下情况会更好：

In your situation (only 2 possibilities), the following will be even better:

if fleechance <= 2:
    print "You failed to run away!"
else:
    print "You got away safely!"

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