逻辑或运算符的行为不符合预期 [英] Logical or operator not behaving as expected

问题描述

def Forest(Health,Hunger):
    print'You wake up in the middle of the forest'
    Inventory = 'Inventory: '
    Squirrel =  'Squirrel'
    while True:
        Choice1 = raw_input('You...\n')
        if Choice1 == 'Life' or 'life':
            print('Health: '+str(Health))
            print('Hunger: '+str(Hunger))
        elif Choice1 == 'Look' or 'look':
            print 'You see many trees, and what looks like an edible dead Squirrel, \na waterfall to the north and a village to the south.'
        elif Choice1 == 'Pickup' or 'pickup':
            p1 = raw_input('Pickup what?\n')
            if p1 == Squirrel:
                if Inventory == 'Inventory: ':
                    print'You picked up a Squirrel!'
                    Inventory = Inventory + Squirrel + ', '
                elif Inventory == 'Inventory: Squirrel, ':
                        print'You already picked that up!'
            else:
                print"You can't find a "+str(p1)+"."
        elif Choice1 == 'Inventory' or 'inventory':
            print Inventory

我试图这样做，当它说
你......
你可以输入Life，Pickup，Look或Inventory。
我在这个程序上有更多的代码我只是向你展示一部分。
但是每次运行它时，即使您键入Pickup或Look或Inventory，它也始终显示Life部分。
请帮忙！
谢谢，
John

I am trying to make it so when it says You... you can type either Life, Pickup, Look, or Inventory. I have way more code on this program I am just showing you a portion. But every time I run it, it always shows the "Life" portion even if you type "Pickup" or "Look" or "Inventory". Please help! Thanks, John

编辑：
我认为这只是一个间距问题，但我不确定它早先运行良好。 ..

I think it's just a spacing issue but I am not sure it was running fine earlier...

推荐答案

您误解或表达式。改为使用它：

You are misunderstanding the or expression. Use this instead:

if Choice1.lower() == 'life':

或者，如果您必须针对多个选项进行测试，请在中使用：

or, if you must test against multiple options, use in:

if Choice1 in ('Life', 'life'):

或者，如果你必须使用或，那么就这样使用它：

or, if you must use or then use it like this:

if Choice1 == 'Life' or Choice1 == 'life':

并将其展开到您的其他 Choice1 测试。

and expand this to your other Choice1 tests.

Choice1 =='Life'或'life'被解释为（Choice1 =='Life'）或（'life'），后一部分总是为True。即使它被解释为 Choice1 ==（'生命'或'生命'），那么后者将评估为'Life' only（布尔测试时为True），所以你要测试 Choice1 =='Life'相反，将选择设置为'life'将永远不会让测试通过。

Choice1 == 'Life' or 'life' is interpreted as (Choice1 == 'Life') or ('life'), with the latter part always being True. Even if it was interpreted as Choice1 == ('Life' or 'life') then the latter part would evaluate to 'Life' only (it being True as far as boolean tests go), so you'd be testing if Choice1 == 'Life' instead, and setting Choice to 'life' would never make the test pass.

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