简化Java中连续的'if'语句 [英] Simplification of successive 'if' statements in Java

问题描述

我有一系列 if 语句，如下所示：

I have a series of if statements, as shown below:

if (board[x+1][y]==true) {
    ar+=1;
}
if (board[x][y+1]==true) {
    ar+=1;
}
if (board[x-1][y]==true) {
    ar+=1;
}
if (board[x][y-1]==true) {
    ar+=1;
}
if (board[x+1][y+1]==true) {
    ar+=1;
}
if (board[x+1][y-1]==true) {
    ar+=1;
}
if (board[x-1][y+1]==true) {
    ar+=1;
}
if (board[x-1][y-1]==true) {
    ar+=1;
}

有没有办法用Java简化/压缩这些语句？

Is there a way to simplify/condense these statements with Java?

推荐答案

只需绕过你关心的位置。跳过框的中心。

Simply loop around the position that you care about. Skipping the center of the "box".

提示：您可以按行然后列或访问2D数组[y] [x] （至少，这就是你如何通过查看代码来翻译董事会）。

Tip: You access a 2D array by row then column, or [y][x] (at least, that's how you'd translate the board from looking at the code).

// int x, y;  // position to look around 
for (int xDiff = -1; xDiff <= 1; xDiff++) {
    for (int yDiff = -1; yDiff <= 1; yDiff++) {
        if (xDiff == 0 && yDiff == 0) continue;
        if (board[y+yDiff][x+xDiff]) { 
            ar += 1;
        }
    }
}

小心 - 超出界限例外未处理

Beware - Out of bounds exception is not handled

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