无论如何缩短if（i == x || i == y）？ [英] Anyway to shorten if ( i == x || i == y)?

问题描述

我试图缩短我的代码，来自：

I tried to shorten my code, from :

if(i== x || i == y || i == z )

到

if (i == ( x || y || z ))

我知道这种方式是错误的，因为我在日志中输入不正确。

I know this way is wrong because I got incorrect i in log.

但是，是否有任何方法可以缩短Objective-C中的代码？

However, is there any method to shorten the code in objective-C ?

推荐答案

如果 x == i 的概率高于 y == i 那么最好把它写成 x == i || y == i 而不是 y == i || x == i 因为如果第一个语句的计算结果为true，则不评估第二个语句（它是短路的）

if there is a higher probability that x==i than y==i then it's better to write it as x==i || y==i as opposed to y==i || x==i because if the first statement evaluates to true, the second one is not evaluated (it's shortcircuited)

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