If Statement中的错误逻辑？ [英] Wrong logic in If Statement?

问题描述

$ repeat_times = mysql_real_escape_string（$ repeat_times）;

$repeat_times = mysql_real_escape_string($repeat_times);

$result = mysql_query("SELECT `code`,`datetime` FROM `fc` ORDER by datetime desc LIMIT 25") or die(mysql_error());

$output .="";
$seconds = time() - strtotime($fetch_array["datetime"]);

if($seconds < 60)
  $interval = "$seconds seconds";
else
 if($seconds < 3600)
     $interval = floor($seconds / 60) . " minutes";
else
    if($seconds < 86400)
         $interval = floor($seconds / 3600) . " hours";
    else
         $interval = floor($seconds / 86400) . " days";

while ($fetch_array = mysql_fetch_array($result)) {

    $fetch_array["code"] = htmlentities($fetch_array["code"]);
    $output .= "<li><a href=\"http://www.***.com/code=" . htmlspecialchars(urlencode($fetch_array["code"])) . "\" target=\"_blank\">" . htmlspecialchars($fetch_array["code"]) . "</a> (" . $interval . ") ago.</li>";

}

$output .="";

return $output;

为什么这个返回janice（14461天）而不是janice（15分钟前）

Why is this returning janice (14461 days) instead of janice (15 minutes ago)

日期时间函数表在我的表中有DATETIME类型，因此它返回日期的完整字符串。

The datetime function table has the DATETIME type in my table so it's returning a full string for the date.

推荐答案

时间计算代码应该进入while循环，因为你想在每个记录的基础上计算时间（它指的是$ fetch_array，它仅作为while循环的一部分被检索） ）

The time calculation code should go inside the while loop, since you want to calculate the time on a per-record basis (that and it's referring to $fetch_array, which is only retrieved as part of the while loop)

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