从另一个应用程序的Android发射活动 [英] Launch Activity from another Application Android
问题描述
可能重复:
<一href="http://stackoverflow.com/questions/3872063/android-launch-an-application-from-another-application">Android从另一个应用程序启动应用程序
Possible Duplicate:
Android Launch an application from another application
我有一个问题,它是下列之一:
I am having a problem and it is the following one:
我有两个应用程序,我想用另外一个启动活动之一,从一个应用程序......我要举一个例子:
I have two applications, and I want to launch one of the activities from one app by the other one......I am gonna give an example:
第一个应用程序包:
es.wul4.android.app1
"es.wul4.android.app1"
第二个应用程序包:
es.wul4.android.app2
"es.wul4.android.app2"
我要的是推出的类名为Identificar
从APP1
What I want is to launch the activity whose class is called "Identificar"
from the app1
这个活动不是主要的一个。我试图通过doind是:
This activity is NOT the main one. I tried by doind that:
Intent intent = getPackageManager().getLaunchIntentForPackage("es.wul4.app2.Identificar");
startActivity(intent);
不过,我所得到的这样做是什么,它告诉我,该应用程序doesn't存在。
But what i get doing that is nothing, it tells me that the app doesn´t exists.
如果我尝试这样做:
getPackageManager().getLaunchIntentForPackage("es.wul4.app2");
startActivity(intent);
和它推出一个活动,但主要是........
And it launch one activity, but the main one........
我怎么能推出这个特别的活动里面包es.wul4.app2.Identificar??
How can I launch this particular Activity inside the package "es.wul4.app2.Identificar"??
ü非常感谢。
推荐答案
您需要使用的意图过滤器是什么
。假设要推出的活动是在包 launch.me
。在这个应用中体现的所有活动(主或其他方式)将由&LT被decalred;活性GT;
标签
假设你要启动的活动是类文件 Launchme
里面。那么你的表现的一部分将是这样的:
What you need to use are intent-filters
. Assume the activity to be launched is in the package launch.me
. Inside this applications manifest all the activities (main or otherwise) will be decalred by the <activity>
tag.
Assuming the activity you want to launch is inside the class file Launchme
. Then a portion of your manifest will be something like:
<activity android:name="launch.me.Launchme"
android:label="@string/app_name">
<intent-filter>
<action android:name="launch.me.action.LAUNCH_IT"/>
<category android:name="android.intent.category.DEFAULT"/>
</intent-filter>
</activity>
现在从要推出上述活动中使用的行为:(注:本次活动可以在任何包中任何地方,你必须确保两个,主叫和被叫套餐都可以在设备上)
Now in the activity from where you want to launch the above activity use:(Note: This activity can be in any package anywhere. You have to make sure that both, the calling and the called packages are available on the device)
Intent i=new Intent();
i.setAction("launch.me.action.LAUNCH_IT");
startActivityForResult(i,0);
您可以采用其他方法来启动意图以外 startActivityForResult
,这就是高达你。
You can use other methods for starting the intent other than startActivityForResult
, thats upto you.
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