if current_user.id = @ game.user_id [英] if current_user.id = @game.user_id

问题描述

我有链接到我项目中每个游戏的节目页面，如果
游戏user_id与当前登录用户的id匹配，那么我想要
它显示编辑按钮，如果它们是然后它不应该显示。

I have links to the show pages for each game in my project and if the games user_id matches the id of the currently signed in user then I want it to display the edit button if they are not then it shouldn't display.

我目前有以下代码集，但它不起作用。每个游戏
都有编辑按钮显示。代码如下：

I currently have the following code set but it doesn't work. Every game has the edit button display. The code is as followed:

 <% if current_user.id = @game.user_id %>
    <div id="text3"><%= link_to 'Edit', edit_game_path(@game) %></div><br />
 <% end %>

任何想法？

推荐答案

MrDanA的回答很可能是错误，但您可能希望更好地使用此代码。像那样检查不是Rails的做法。相反，制作一个用户实例方法，如：

MrDanA's answer is most probably the error, but you may want to make this code better. Checking like that is not the Rails way of doing it. Instead, make a User instance method like :

def has_game?(game)
  self.games.exists?(:id => game.id)
end

然后在您的视图中：

<% if current_user.has_game?(@game) %> ...

（甚至可以通过进一步委托存在于游戏模型中作为范围或更好所以，如果你愿意的话）

(can even be better by further delegating exists into the game model, as a scope or so, if you like)

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