Python:在循环中解析JSON [英] Python: parse JSON in loop
问题描述
我有一个功能,从数据库中提取国家,城市,纬度,经度
,并在Yelp API上搜索特定业务。
I have a function that pick-ups Country,City,Latitude,Longitude
from a database and search on Yelp API for particular business.
一切正常:
def get_movietheaters_for(country, city, latitude, longitude):
connection2 = pyodbc.connect('DRIVER={SQL Server};'
'SERVER=ASPIRES3;'
'DATABASE=worldcitiespop;'
'UID=sqlninja;'
'PWD=sqlninja')
cursor2 = connection2.cursor()
# Call Yelp API to pull business data
# (Yelp v3 API: https://nz.yelp.com/developers/documentation/v3)
url = 'https://api.yelp.com/v3/businesses/search'
params = {'cc': country,
'location': city,
'cll': "%s,%s" % (latitude, longitude),
'categories': args.category,
'limit': args.limit}
response = requests.get(url = url, headers = headers, params=params)
# if response.status_code == 200:
response_data = response.json()
sqlStatement = "INSERT INTO VistaYelp (ID, Name, City, Zip_code, Country, State, Address1, Address2, Address3, Latitude, Longitude, Phone, Yelp_URL, Review_Count, Rating) values (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?)" # Query
# Here we go to store JSON elements for SQL
for SQL_element in response_data['businesses']:
SQL_ID = SQL_element['id']
SQL_Name = SQL_element['name']
SQL_City = SQL_element['location']['city']
SQL_Zip_code = SQL_element['location']['zip_code']
SQL_Country = SQL_element['location']['country']
SQL_State = SQL_element['location']['state']
SQL_Address1 = SQL_element['location']['address1']
SQL_Address2 = SQL_element['location']['address2']
SQL_Address3 = SQL_element['location']['address3']
SQL_Latitude = SQL_element['coordinates']['latitude']
SQL_Longitude = SQL_element['coordinates']['longitude']
SQL_Phone = SQL_element['phone']
SQL_YelpURL = SQL_element['url']
SQL_Review = SQL_element['review_count']
SQL_Rating = SQL_element['rating']
if args.do == 'show':
print (SQL_ID,SQL_Name,SQL_City,SQL_Zip_code,SQL_Country,SQL_State,
SQL_Address1,SQL_Address2,SQL_Address3,SQL_Latitude,SQL_Longitude,SQL_Phone)
elif args.do == 'save':
cursor2.execute(sqlStatement, SQL_ID,SQL_Name,SQL_City,SQL_Zip_code,SQL_Country,SQL_State,SQL_Address1,SQL_Address2,SQL_Address3,SQL_Latitude,SQL_Longitude,SQL_Phone,SQL_YelpURL,SQL_Review,SQL_Rating)
connection2.commit()
if args.do == 'show':
print ('\nTotal Cinemas found: ' , len(response_data['businesses']),' for Latitude and Longitude ', latitude, longitude)
elif args.do == 'save':
print ('\nTotal Cinemas found and saved in database: ' , len(response_data['businesses']),' for', latitude, longitude)
当脚本搜索不存在或不在Yelp数据库中的城镇时出现问题,因此JSON调用会返回我:
Problem start when the script search for a town that doesn't exists or is not in the Yelp database, so JSON call returns me:
{
"error": {
"code": "LOCATION_NOT_FOUND",
"description": "Could not execute search, try specifying a more exact location."
}
}
脚本死于痛苦(我的痛苦其实):
and the script dies in terrible pain (my pain actually):
这对我来说很有意义,Python说:
And it make sense to me, Python is saying:
for SQL_element in response_data['businesses']:
KeyError: 'businesses'
翻译的意思是:嘿伙计,你知道'企业'的JSON元素,在这里没有这样的元素响应,所以我不知道该怎么做,所以我就此止步。
Which translated means:"Hey dude, you know 'businesses' JSON element, there is no such element in the response, so I don't know what to do, so I stop here."
我如何构建类似的东西:继续做你的工作和如果response_data ['error'] ['code'] =='LOCATION_NOT_FOUND':
什么都不做?
How can I structure something like: keep doing your job and if response_data['error']['code'] == 'LOCATION_NOT_FOUND':
do nothing?
推荐答案
if 'businesses' in response_data:
for SQL_element in response_data['businesses']:
…
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