R中的If语句出错 [英] Error in If statment in R
问题描述
下面是代码。似乎我没有设法正确定义向量'nobs','cor'并且if语句试图评估NA值。
有人能指出我的错误吗?
谢谢,
Tamir
below is the code. It seems I have not managed to define the vectors 'nobs', 'cor' correctly and the if statement is trying to asses an NA value. Can someone point me my error? Thanks, Tamir
corr<-function(directory, threshold=0){
allfiles<-list.files("specdata", full.names = TRUE)
NumOfFiles<-length(allfiles)
n<-1
id<-vector()
nobs<-vector()
cor<-vector()
for (i in NumOfFiles){
data<-read.csv(allfiles[i])
cleandata<-data[complete.cases(data),]
id[n]=i
nobs[n]<-sum(complete.cases(data)) #Number of completre cases
n<-n+1
if (nobs[n]>threshold){
cor[n]<-cor(cleandata[sulfate],cleandata[nitrate])
}
}
return(cor)
}
推荐答案
代码并不遥远。我改变了 n< - n + 1
的位置。在您的示例中,它在函数中过早递增。当函数下降到 if(nobs [n]> threshold)
时,它检查你做了n + 1,所以总是 NA
。
The code wasn't that far off. I changed the position of n <- n+1
. In your example, it was incrementing too early in the function. When the function got down to if(nobs[n]>threshold)
it was checking AFTER you did n+1, so it was always NA
.
其次,我在污染物名称周围加上引号。
Secondly, I put quotes around the pollutant names.
corr<-function(directory, threshold=0){
allfiles<-list.files("specdata", full.names = TRUE, pattern="csv")
NumOfFiles<-length(allfiles)
n<-1
id<-vector()
nobs<-vector()
cor<-vector()
for (i in 1:NumOfFiles){
data<-read.csv(allfiles[i])
cleandata<-data[complete.cases(data),]
id[n]=i
nobs[n]<- sum(complete.cases(data)) #Number of completre cases
if (nobs[n]>threshold){
cor[n]<-cor(cleandata[,"sulfate"],cleandata[,"nitrate"])
n<-n+1
}
}
return(cor)
}
我们可以测试:
summary(corr("specdata"))
Min. 1st Qu. Median Mean 3rd Qu. Max.
-1.00000 -0.05205 0.10840 0.13800 0.27890 1.00000
cr <- corr("specdata", 150)
head(cr)
[1] -0.01895754 -0.14051254 -0.04389737 -0.06815956
[5] -0.12350667 -0.07588814
其中两个匹配期望输出。
Which both match the desired output.
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