有没有办法让PHP检测到损坏的图像？ [英] Is there any way to have PHP detect a corrupted image?

问题描述

有没有办法让PHP确定图像文件是否已损坏且无法正常显示？

Is there any way to have PHP determine whether an image file is corrupted and will not be able to display properly?

我试过检查 fopen 并检查网址是否有效，但是没有用！

I've tried to check with fopen and check whether the URL is valid, but it hasn't worked!

推荐答案

Javascript解决方案（涉及jQuery，虽然这应该可以不用它）：

Javascript solution (with involving jQuery, though this should be possible to do without it too):

<script type='text/javascript'>
    $(function(){
        var files = [
            'warning-large.png',
            'warning-large-corrupted.png',
            'http://www.example.com/none.gif',
            'http://sstatic.net/stackoverflow/img/favicon.ico'
        ];
        for ( var n in files ) {
            var img = $('<img/>');
            img.error(function(){
                alert('error:\n' + this.src);
            });
            img.load(function(){
                alert('success:\n' + this.src);
            });
            img.attr('src', files[n]);
        }
    });
</script>

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