PHP从application / octet流创建图像 [英] PHP create image from application/octet stream

问题描述

我的应用程序是从内容类型为application / octet-stream的移动设备发送给它的图像。

My application is having images sent to it from mobile devices with the content-type "application/octet-stream".

我需要使用以下方法处理这些图像GD库，这意味着我需要能够从数据中创建一个图像对象。

I need to process these images using the GD library, which means I need to be able to create an image object from the data.

通常，我一直在使用imagecreatefromjpeg，imagecreatefrompng，imagecreatefromgif等来处理从Web表单上传的文件，但是当我作为application / octet-stream来找我时，这些文件似乎不起作用。

Typically, I have been using imagecreatefromjpeg, imagecreatefrompng, imagecreatefromgif, etc, to handle files uploaded from web forms, but these don't seem to work when coming to me as application/octet-stream.

关于如何实现目标的任何想法？

Any ideas on how I can achieve my goal?

编辑

这是我用来创建图像标识符的代码...我的处理程序在整个过程中完美运行我的网站，我可以告诉我的网站和iOS数据之间的唯一区别是内容类型

Here is the code I use to create the image identifier...my handler works perfectly throughout my site, the only difference I can tell between my site and the data from the iOS is the content-type

public function open_image($path) {
        # JPEG:
        $im = @imagecreatefromjpeg($path);
        if ($im !== false) { $this->image = $im; return $im; }

        # GIF:
        $im = @imagecreatefromgif($path);
        if ($im !== false) { $this->image = $im; return $im; }

        # PNG:
        $im = @imagecreatefrompng($path);
        if ($im !== false) { $this->image = $im; return $im; }

        $this->error_messages[] = "Please make sure the image is a jpeg, a png, or a gif.";
        return false;
    }

推荐答案

简单：）

$image = imagecreatefromstring( $data );

具体来说：

$data = file_get_contents($_FILES['myphoto']['tmp_name']);
$image = imagecreatefromstring( $data );

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