如何在Java中Stich to Image对象 [英] How to Stich to Image objects in Java

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本文介绍了如何在Java中Stich to Image对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个场景,我从我的地图服务器获得了许多图块(例如12)。现在对于缓冲和离线功能,我需要再次将它们连接起来,这样我们就必须处理1个单个图像对象而不是12个。我试过没有JAI,我的代码在下面。

I have a scenario in which i`m getting a number of tiles (e.g.12) from my mapping server. Now for buffering and offline functions I need to join them all back again so that we have to deal with 1 single image object instead of 12. I ve tried to do it without JAI my code is below.

package imagemerge;


import java.awt.*;
import java.awt.image.*;
import java.awt.event.*;

public class ImageSticher extends WindowAdapter {

    Image tile1;
    Image tile2;
    Image result;
    ColorModel colorModel;
    int width,height,widthr,heightr;
    //int t1,t2;
    int t12[];


    public ImageSticher()
    {

    }

    public ImageSticher (Image img1,Image img2,int w,int h)
    {
        tile1=img1;
        tile2=img2;

        width=w;
        height=h;
        colorModel=ColorModel.getRGBdefault();

    }

    public Image horizontalStich() throws Exception
    {

        widthr=width*2;
        heightr=height;

        t12=new int[widthr *  heightr];

        int t1[]=new int[width*height];
        PixelGrabber p1 =new PixelGrabber(tile1, 0, 0, width, height, t1, 0, width);
        p1.grabPixels();

        int t2[]=new int[width*height];
        PixelGrabber p2 =new PixelGrabber(tile2, 0, 0, width, height, t1, 0, width);
        p2.grabPixels();

        int y, x, rp, rpi;
        int red1, red2, redr;
        int green1, green2, greenr;
        int blue1, blue2, bluer;
        int alpha1, alpha2, alphar;

        for(y=0;y<heightr;y++)
        {
            for(x=0;x<widthr;x++)
            {
                //System.out.println(x);
                rpi=y*widthr+x; // index of resulting pixel;
                rp=0;           //initializing resulting pixel
                System.out.println(rpi);

                if(x<(widthr/2)) // x is less than width , copy first tile
                {
                    //System.out.println("tile1="+x);
                    blue1 = t1[rpi] & 0x00ff; // ERROR occurs here
                    green1=(t1[rpi] >> 8) & 0x00ff;
                    red1=(t1[rpi] >> 16) & 0x00ff;
                    alpha1 = (t1[rpi] >> 24) & 0x00ff;

                    redr = (int)(red1 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
                    redr = (redr < 0)?(0):((redr>255)?(255):(redr));
                    greenr = (int)(green1 * 1.0); //
                    redr = (int)(red1 * 1.0); //
                    greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
                    bluer = (int)(blue1 * 1.0);
                    bluer =  (bluer < 0)?(0):((bluer>255)?(255):(bluer));
                    alphar = 255;

                    //resulting pixel computed
                    rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);


                }
                else // index is ahead of half way...copy second tile
                {

                    blue2 = t2[rpi] & 0x00ff; // blue band bit of first tile
                    green2=(t2[rpi] >> 8) & 0x00ff;
                    red2=(t2[rpi] >> 16) & 0x00ff;
                    alpha2 = (t2[rpi] >> 24) & 0x00ff;

                    redr = (int)(red2 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye
                    redr = (redr < 0)?(0):((redr>255)?(255):(redr));
                    greenr = (int)(green2 * 1.0); //
                    redr = (int)(red2 * 1.0); //
                    greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr));
                    bluer = (int)(blue2 * 1.0);
                    bluer =  (bluer < 0)?(0):((bluer>255)?(255):(bluer));
                    alphar = 255;

                    //resulting pixel computed
                    rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff);


                }
                t12[rpi] = rp; // copying resulting pixel in the result int array which will be converted to image

            }
        }

        MemoryImageSource mis;
        if (t12!=null) {
            mis = new MemoryImageSource(widthr, heightr, colorModel, t12, 0, widthr);
            result = Toolkit.getDefaultToolkit().createImage(mis);
            return result;

        }
        return null;

    }





}

现在检查我的理论我 m试图加入或者stich两个tile视频但我 m得到错误:

now to check the my theory Im trying to join or stich two tiles horizontaly but im getting the error :

java.lang.ArrayIndexOutOfBoundsException:90000
at imagemerge.ImageSticher.horizo​​ntalStich(ImageSticher.java:69)
at imageStream.ImageStream.getImage(ImageStream .java:75)
at imageStream.ImageStream.main(ImageStream.java:28)

java.lang.ArrayIndexOutOfBoundsException: 90000 at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69) at imageStream.ImageStream.getImage(ImageStream.java:75) at imageStream.ImageStream.main(ImageStream.java:28)

是否有某种限制因为当stiching两个300的图像x 300水平意味着结果图像将是600 x 300 ...这将使180000索引大小,但它在90000给出错误,我在这里做错了什么

is there some kind of limitation because when stiching two images of 300 x 300 horizontally it means the resulting image will be 600 x 300 ... that would make 180000 index size but its giving error at 90000, what am I doing wrong here

推荐答案

rpi 是结果像素的索引,而不是 t1中源图块数据中的索引,这是一半大小。

rpi is the index of your resulting pixel, not the index in your source tile data in t1, which is half the size.

这篇关于如何在Java中Stich to Image对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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