通过单击picturebox1 c＃在Windows照片查看器中打开图像 [英] open the image in windows photo viewer by clicking on picturebox1 c#

问题描述

我有一个带有SQlite数据库的项目。我将图像保存在pics文件夹中（进入调试文件夹）&他们在数据库中的名称（列docpic）。当我连续点击时，相关图像将图像从数据库检索到picturebox1。我想通过点击picturebox1打开windows photo viewer打开图像（在picturebox1中）。
怎么办呢？

I have a project with SQlite database . I save images in folder " pics " ( into debug folder) & their name in the database ( column "docpic") . When I click in a row , related image retrieve the image from database to picturebox1 . i want open the image ( in picturebox1 ) by windows photo viewer by clicking on picturebox1 . how can do this ?

我在picturebox1点击事件中使用这些代码，但这不起作用：

i use this codes in picturebox1 click event but thats not work :

if (pictureBox1.Tag != null)
{
    System.Diagnostics.Process imageViewerProcess = new System.Diagnostics.Process();
    imageViewerProcess.StartInfo.CreateNoWindow = false;
    imageViewerProcess.StartInfo.FileName = "rundll32.exe";
    imageViewerProcess.StartInfo.Arguments =
            @"C:\WINDOWS\System32\shimgvw.dll,ImageView_Fullscreen "
                               + pictureBox1.Tag.ToString();
    imageViewerProcess.Start();
}

}

推荐答案

你在参数中遗漏了一些东西，因为它必须有正确的路径

如果你使用的是Windows 7 64位，那么改变
C：\ Windows\system32 到你的参数代码行中的 C：\ Windows \SysWOW64 。
所以它变成：

you missing something in the argument , because it must have the correct path
and if you are using Windows 7 64-bit then change
C:\Windows\system32 to C:\Windows\SysWOW64 inside your argument code line .
so it become :

imageViewerProcess.StartInfo.Arguments = 
      @"C:\Windows\SysWOW64\shimgvw.dll,ImageView_Fullscreen "+ pictureBox1.Tag.ToString();

---

和 相反 ：

---

and instead of all your code you can shortly use :

• 简单使用：

System.Diagnostics.Process.Start(@"Directory + image name");

---

用于高级用法：

System.Diagnostics.Process.Start(new System.Diagnostics.ProcessStartInfo(){
                FileName  = @"Directory + image name",
                UseShellExecute = true,
                Verb  = "open"
               });

---

另一种方式：

ProcessStartInfo startInfo = new ProcessStartInfo(@"Directory + image name");
                             startInfo.Verb = "open";
                             System.Diagnostics.Process.Start(startInfo);

---

and ofcourse改变这个：目录+图像名称到您的图像路径。

and ofcourse change this: "Directory + image name" to your image path.

• 注意：必须是完整路径
  
       ;      例如： c：\ folder\image.jpg ，
  
            ;  而不仅仅是 image.jpg

• Note: its necessary to be complete path
             example : c:\folder\image.jpg ,
             and not just image.jpg

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